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Vlad1618 [11]
3 years ago
15

A father decided to give twenty five percent of his monthly income to his three children as their monthly allowance. The eldest

child got forty five percent of the allowance and the youngest got twenty percent. How much did the youngest child receive if the second child got three thousand five hundred dollars?
Mathematics
1 answer:
Helen [10]3 years ago
3 0

Answer:

The youngest child will receive $2000

Step-by-step explanation:

A father decided to give 25% of his monthly income to his three children as their monthly allowance.

The eldest child got 45% of the allowance and the youngest got 20%. This means that the second child got:

100 - (45 + 20) = 100 - 65 = 35%

The second child received $3500.

Let the 25% of his monthly income be x.

Hence:

35% of x = 3500

=> \frac{35}{100} * x = 3500

x = \frac{3500 * 100}{35}

x = $10000

The amount the man shared among his children is $10000.

Hence, the youngest child (20%) will receive:

20% of $10000

\frac{20}{100} * 10000

= $2000

The youngest child will receive $2000.

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VladimirAG [237]

Answer:

The possible length of the triangle =

1) (1inches, 196inches)

2) (2incheq, 98inches)

3) (4inches , 49 inches)

4) (7 inches , 28 inches)

Step-by-step explanation:

We are told the above Triangle is not an Isosceles Triangle

Hence, we assume it is a right angle triangle

The area of a triangle is = 1/2 × Base × Height

= let us represent Base and Height = x

Hence:

1/2 × x × x = 98

x² /2 = 98

Cross Multiply

x² = 98 × 2

x² = 196

Step 2

We find the factors of 196

1× 196 = 196 (1, 196)

2 × 98 = 196 (2, 98)

4 ×49 = 196 (4, 49)

7 × 28 = 196 (7, 28)

Therefore, all the possible length of the triangle =

1) (1inches, 196inches)

2) (2incheq, 98inches)

3) (4inches , 49 inches)

4) (7 inches , 28 inches)

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We know that a class interval must be greater than what the I formula solution is; however... What is the solution for class int
stich3 [128]

Answer:

Therefore the answer is 20.

Step-by-step explanation:

We know that

class interval = range / number of classes

But here number of classes is not given , so we use the formula

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where , range =maximum - minimum = 220-100 = 120

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Rounding up to a convinient number

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the cost of running an appliance varies jointly as the number of watts used, the hours of operation, and the cost per kilo-watt
zhuklara [117]
Suppose:
C=cost
c=cost per kilo-watt hour
w=number of watts
h=number of hours
thus
C=kwhc
where:
k=constant of proportionality:
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but
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thus
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when 
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