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Kay [80]
2 years ago
6

On a certain hot summer day, 738 people used the public swimming pool.The daily prices are 1.50 for children and 2.00 for adults

.The receipts for admission totaled 1306.00 .How many children and how many adults swam at the public pool that day?
Mathematics
1 answer:
Artemon [7]2 years ago
7 0

Answer:

A = 340 adult.

C = 398 children.

Step-by-step explanation:

Let the number of children be C

Let the number of adults be A

Translating the word problem into an algebraic equation, we have;

A + C = 738  .......equation 1

1.5C + 2C = 1306  .......equation 2

A = 738 - C .......equation 3

Substituting eqn 3 into eqn 2, we have;

1.5(738 - C) + 2C = 1306

1107 - 1.5C + 2C = 1306

1306 - 1107 = 2C - 1.5C

199 = 0.5C

C = 199/0.5

<em>C = 398 children. </em>

Now, to find the value of A.

From equation 3;

A = 738 - C

A = 738 - 398

<em>A = 340 adult. </em>

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Answer:

0.5 < x < 16.5

Step-by-step explanation:

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But there is also a lower restriction, given by:

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Because S2 > S1, the first inequality is more restrictive, so we need to use that one.

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=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}

Step-by-step explanation:

\begin{pmatrix}-3&4\\2&-5\end{pmatrix}\begin{pmatrix}3&-2\\ 1&0\end{pmatrix}

Multiply the row of the first matrix to the column of the second matrix

\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=\left(-3\right)\cdot \:3+4\cdot \:1

\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=\left(-3\right)\left(-2\right)+4\cdot \:0

\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=2\cdot \:3+\left(-5\right)\cdot \:1\

\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=2\left(-2\right)+\left(-5\right)\cdot \:0\

=\begin{pmatrix}\left(-3\right)\cdot \:3+4\cdot \:1&\left(-3\right)\left(-2\right)+4\cdot \:0\\ 2\cdot \:3+\left(-5\right)\cdot \:1&2\left(-2\right)+\left(-5\right)\cdot \:0\end{pmatrix}

simplifying them we get

=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}

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