Answer:
The answer is below
Explanation:
Given that:
Frame transmission time (X) = 40 ms
Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request
a) Probability that there is success on the first attempt =
but k = 0, therefore Probability that there is success on the first attempt = 
b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)
P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = ![[1-e^{-G}]^k=[1-0.135]^k=0.865^k](https://tex.z-dn.net/?f=%5B1-e%5E%7B-G%7D%5D%5Ek%3D%5B1-0.135%5D%5Ek%3D0.865%5Ek)
P(success in k+1 attempt) = 
Probability of exactly k collisions and then a success = 
c) Expected number of transmission attempts needed = probability of success in k transmission = 
My personal favorite is Metal gear solid 3: <em>Snake eater</em>.
Answer:
1. 5
2. Because they let us quickly process the contents of an array, which have many values.
Explanation:
Answer:
"
CRL (certificate revocation list)" is the appropriate answer.
Explanation:
- A collection of such subscriber bases containing accreditation or certification status combined with the validation, revocation, or outdated certification within each final customer is known as CRL.
- Only certain subscribing workstations with a certain underlying cause authentication system should have been duplicated.
You could assign values to variables and break it up into if else-if else statements.
<span>Pseudocode:</span>
if a < b and b < c:
print("increasing")
else if a > b and b > c:
print("decreasing")
else:
print("neither")
Hope this helps.