A specific amount or number that represent how much of something you have is ____

Which statements describe the graph of y = 3√x-1+2 ? Check all that apply.

Reptile [31]

Answer:

The correct options are A, D and E.

Step-by-step explanation:

We are given the function $y=\sqrt[3]{x-1} +2$

From the graph below, we see that,

Domain and range of the function is the set of all real numbers.

As y-intercept is the point where the graph of the function crosses y-axis.

That is, y-intercept is obtained when x= 0.

So, on substituting, we have,

$y=\sqrt[3]{0-1} +2$

i.e. $y=-1+2$

i.e. y= 1

Thus, the y-intercept is (0,1).

Also, x-intercept is the point where the graph of the function crosses x-axis.

That is, x-intercept is obtained when y= 0.

So, on substituting, we have,

$0=\sqrt[3]{x-1} +2$

i.e. $-2=\sqrt[3]{x-1}$

i.e. $-8=x-1$

i.e. x= -7

Thus, the x-intercept is (-7,0).

Hence, the correct options for the function are,

A. The graph has a domain of all real numbers.

D. The graph has a y-intercept at (0, 1)

E. The graph has an x-intercept at (–7, 0).

3 0

3 years ago

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What is the value of x in the equation below?

belka [17]

$remember$
$ln(a^b)=bln(a)$
$ln(e)=1$
$so$
$ln(e^x)=xln(e)=x$

$1+2e^{x+1}=9$
$minus \space\ 1 \space\ both \space\ sides$
$2e^{x+1}=8$
$divide \space\ both \space\ sides \space\ by \space\ 2$
$e^{x+1}=4$
$take \space\ ln \space\ of \space\ both \space\ sides$
$ln(e^{x+1})=ln(4)$
$(x+1)ln(e)=ln(4)$
$x+1=ln(4)$
$minus \space\ 1 \space\ from \space\ both \space\ sides$
$x=ln(4)-1$
$answer \space\ is \space\ C=ln(4)-1$

5 0

3 years ago

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Help plz plz plz :)

murzikaleks [220]

Answer:

x= 3/5 or x= 0.6

Step-by-step explanation:

8 0

3 years ago

Lines 3x-2y+7=0 and 6x+ay-18=0 is perpendicular. What is the value of a?

BlackZzzverrR [31]

Answer:

$\boxed{\sf a = 9 }$

Step-by-step explanation:

Two lines are given to us which are perpendicular to each other and we need to find out the value of a . The given equations are ,

$\sf\longrightarrow 3x - 2y +7=0$

$\sf\longrightarrow 6x +ay -18 = 0$

Step 1 : Convert the equations in slope intercept form of the line .

$\sf\longrightarrow y = \dfrac{3x}{2} +\dfrac{ 7 }{2}$

and ,

$\sf\longrightarrow y = -\dfrac{6x }{a}+\dfrac{18}{a}$

Step 2: Find the slope of the lines :-

Now we know that the product of slope of two perpendicular lines is -1. Therefore , from Slope Intercept Form of the line we can say that the slope of first line is ,

$\sf\longrightarrow Slope_1 = \dfrac{3}{2}$