Answer:
D.
Step-by-step explanation:
The problem is asking to multiply x-5 by x^2, so we can set it up to distribute the x^2 to both values. The final answer would therefore be x^2(x-5), which is D.
5 so yea I think that’s what you looking for
Ok, so here, we need to use the slope formula which is:
(y2 - y1)/(x2-x1)
y2 = 9
y1 = 5
x2 = x
x1 = 10
So:
(9-5)/(x-10) = -2
Now, we just solve for x,
9-5 = -2(x-10)
4 = -2x+20
2x = 16
x = 8
C) Moe highest probability=14, median (50% of the values), mean=central measure of the '50%' all are 14-15, C) is the closest, no? :)
Answer:
21
Step-by-step explanation:
![\left[\begin{array}{cc}5&9\\-6&9\end{array}\right] +6\left[\begin{array}{cc}-5&2\\7&8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%269%5C%5C-6%269%5Cend%7Barray%7D%5Cright%5D%20%2B6%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-5%262%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Multiply the second matrix by 6.
![\left[\begin{array}{cc}5&9\\-6&9\end{array}\right] +\left[\begin{array}{cc}-30&12\\42&48\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%269%5C%5C-6%269%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-30%2612%5C%5C42%2648%5Cend%7Barray%7D%5Cright%5D)
Add the corresponding cells in each matrix.
![\left[\begin{array}{cc}5-30&9+12\\-6+42&9+48\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5-30%269%2B12%5C%5C-6%2B42%269%2B48%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{cc}-25&21\\36&57\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-25%2621%5C%5C36%2657%5Cend%7Barray%7D%5Cright%5D)