First we distribute 3 into 2x and -4.
3 x 2x = 6x
3 x -4 = -12
That will make the left side of the equation:
6x - 12 = 5x + 2
Now we subtract 5x on both sides of the equation.
x - 12 = 2
Finally we add 12 on both sides of the equation.
x = 14 is the answer
Answer: 3x + (-4) = x + 2
Step-by-step explanation:
Hope it helps
Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Answer:
7v^3+3v^2-9v
Step-by-step explanation:
This is the simplified version
<span>
<u><em>The correct answer is: </em></u>4.2 inches.
<u><em>Explanation</em></u><span>
<u><em>: </em></u>We use the size of the largest dimension of the reproduction to find the scale factor. The largest dimension of the original drawing was 5 inches.
The largest dimension of the reproduction is 11 inches.
<u>To find the scale factor, divide: </u>
</span></span>

<span><span>=2.1.
Since the scale factor is 2.1, to find the smallest dimension of the reproduction we <u>multiply the original by 2.1</u>:
2*2.1=4.2 inches.</span></span>