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Elza [17]
3 years ago
10

Earth’s diameter at the equator is 7,926 miles. Find the distance around the Earth at the equator.

Mathematics
1 answer:
Doss [256]3 years ago
7 0

Answer:

24,900 miles

Step-by-step explanation:

Circumference = pi × d

Pi × 7926

24,900.263372352

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A height of 12 and a volume of 1.356.48 what is the radius of the cylinder?
alexgriva [62]

Answer:

11.99 ft

Step-by-step explanation:

The formula for the volume of a cyl. of radius r and height h is V = πr²h.

Solving this immediately for h yields:

        V

h = ----------

        πr²

Inserting the known quantities results in:

        V           1356.48 ft³

h = ---------- = ----------------------      Note that r = (1/2)d, so r = (1/2)(12 ft) = 6 ft

        πr²         3.14159 (6 ft)²

  =   11.994 ft

The height of the cyl. is 11.99 ft (to the nearest hundredth foot)

8 0
3 years ago
Find the value of x in the figure
marissa [1.9K]
23 + 2 = 25+65 = 90 degrees
4 0
3 years ago
What is 166.44 dived by 4. PLEASE USE LONG DIVISION. The person who USES LONG DIVISION TO GET THE ANSWER GETS 10 points and brai
ArbitrLikvidat [17]

Answer:

41.61

Step-by-step explanation:

Just divide.

\begin{matrix}4\overline{|\smallspace166.44}\:\:\:\:\:\:\:\end{matrix}


5 0
1 year ago
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Marta_Voda [28]

Answer:


Step-by-step explanation:

2.) −$180/year


6 0
3 years ago
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11. Mr Lee bought a second hand car for
Marrrta [24]

Answer :

Depends on the rate compound interest is accrued. See answers.

Step-by-step explanation:

We need the compound interest formula which is:

A = P (1+\frac{r}{n} )^{nt}

A =  final amount

P =  initial principal balance

r =  interest rate

n =  number of times interest applied per time period

t =  number of time periods elapsed

It doesn't say how frequently the interest is compounded, so we will do monthly, quarterly, and yearly.

MONTHLY

So we know the car costs $25,480 and he made a down payment of $10,000. By subtracting the down payment from the purchase price we find the loan amount.

$25,480 - $10,000 = $15,480

P = 15,480

r = 4.75% = .0475

n = 12  (12 months in a year)

t = 2  

Plug everything into the compound interest formula.

A = P (1+\frac{r}{n} )^{nt}

A = 15480(1+\frac{.0475}{12})^{12*2}

A = 15480(1+\frac{.0475}{12})^{24}

A = 15480(1+.00396)^{24}

A = 15480(1.00396)^{24}

A = 15480*1.0992

A = $17016.14

Mr. Lee paid $17,016.14 when the bill came due at 2 years with interest compounded monthly.

QUARTERLY

P = 15,480

r = 4.75% = .0475

n = 4  (4 quarters in a year)

t = 2  

A = P (1+\frac{r}{n} )^{nt}

A = 15480(1+\frac{.0475}{4})^{4*2}

A = 15480(1+\frac{.0475}{4})^{8}

A = 15480(1+.0119})^{8}

A = 15480(1.0119)^{8}

A = 15480*1.099

A = 15480(1.099)

A = 17013.20

Mr. Lee paid $17,013.20 when the bill came due at 2 years with interest compounded quarterly.

YEARLY

P = 15,480

r = 4.75% = .0475

n = 1  

t = 2  

A = P (1+\frac{r}{n} )^{nt}

A = 15480(1+\frac{.0475}{1})^{1*2}

A = 15480(1+\frac{.0475}{12})^{2}

A = 15480(1+.0475})^{2}

A = 15480(1.0475)^{2}

A = 15480*1.0973

A = 16985.53

Mr. Lee paid $16,985.53  when the bill came due at 2 years with interest compounded yearly.

4 0
3 years ago
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