Write an expression for the perimeter of the triangle shown below

You are playing a game in which a single die is rolled. If a 2 or 5 comes up you win $36. Otherwise, you lose $36. What is your

algol13

1/3 wins and 2/3 losses
given 2 and 5 = 2/6 = 1/3
1, 3, 4, and 6 = 4/6 = 2/3

7 0

3 years ago

4. From 5 faculty members, a committee of 2 is to be formed. In how many ways can this be done?

ohaa [14]

Answer:

3

Step-by-step explanation:

7 0

3 years ago

every 1/2 mile along a hiking path there is water fountain, every 1/4 mile there is a bench, and every 1/8 mile there is a marke

defon

Bench and mile marker

7 0

3 years ago

Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0

3 years ago

Read 2 more answers

Ginger buys lunch at school every day. She always gets

shepuryov [24]

Answer:

The estimated probability that Ginger will eat a a pizza everyday of the week is;

D. 8/10 = 80%

Step-by-step explanation:

The given parameters are;

The frequency with which Ginger buys launch = Everyday

The percentage of the time the cafeteria has pizza out = 80%

The outcome of 0 and 1 = No pizza available

The outcome of 2, 3, 4, 5, 6, 7, 8, and 9 = Pizza available

Therefore, we have the;

Group number ${}$ Percentage of time pizza available

1 ${}$ 80%

2 ${}$ 80%

3 ${}$ 80%

4 ${}$ 80%

5 ${}$ 40%

6 ${}$ 100%

7 ${}$ 80%

8 ${}$ 100%

9 ${}$ 80%

10 ${}$ 80%

Therefore, the sum of the percentages outcome the days Ginger eats pizza = 0.8 + 0.8 + 0.8 + 0.8 + 0.4 + 1 + 0.8 + 1 + 0.8 + 0.8 = 8

The number of runs of simulation = 10 runs

The estimated probability that Ginger will eat a a pizza everyday of the week = (The sum of the percentages outcome the days Ginger eats pizza)/(The number of runs of simulation)

∴ The estimated probability that Ginger will eat a a pizza everyday of the week = 8/10

6 0

3 years ago

Read 2 more answers