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3 years ago

How is multiplication of two integers represented on a number line and a chip board?

Mathematics

1 answer:

labwork [276]3 years ago

8 0

Can you give me an example? Thank you

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I need on help on this!

ElenaW [278]

The probability that the marble taken out is yellow is 1/4

Step-by-step explanation:

Total marbles = 12

Yellow marbles = 3

Probability that the marble taken out is yellow= No of yellow marbles/total marbles.

Probability that the marble taken out is yellow= 3/12

Probability that the marble taken out is yellow= 1/4

So, the Probability that the marble taken out is yellow is 1/4

Keywords: Probability

Learn more about Probability at:

#learnwithBrainly

7 0

3 years ago

A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte

Over [174]

Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if the mean difference is of 0.7 or less, that is:

$H_0: \mu \leq 0.7$

At the alternate hypothesis, we test if the mean difference is greater than 0.7, that is:

$H_1: \mu > 0.7$

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that $\mu = 0.7$

A survey of 35 people was conducted to compare their self-reported height to their actual height.

This means that $n = 35$

From the sample, the mean difference was 0.95, with a standard deviation of 0.44.

This means that $X = 0.95, s = 0.44$

Calculate the test statistic

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}$

$t = 3.36$

The test statistic is t = 3.36.

3 0

3 years ago

Identify the equivalent expression for (m^1/3 m^1/5)^0

Lostsunrise [7]

Answer:

Step-by-step explanation:

The thing is, x^0 is always 1. So even if you simplify, it will still be 1.

$(m^\frac{1}{3}*m^\frac{1}{5})^0\\(m^\frac{8}{15})^0\\\text{But when put to the power of 0,}\\1.$

4 0

3 years ago

Read 2 more answers

Which polynomial correctly combines the like terms and puts the given polynomial in standard form?

Minchanka [31]

Answer: $-5x^3y^3+8x^4y^2-7xy^5+x^2y^4+8x^6$

Step-by-step explanation:

$-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5$

$-5x^3y^3+8x^4y^2+(-xy^5-6xy^5)+(-2x^2y^4+3x^2y^4)+8x^6$

$-5x^3y^3+8x^4y^2+(-7xy^5)+(x^2y^4)+8x^6$

$-5x^3y^3+8x^4y^2-7xy^5+x^2y^4+8x^6$

8 0

3 years ago

Read 2 more answers

A: Length: 5y Width: x+2y

iVinArrow [24]

The answer would be C I’m not sure

3 0

2 years ago