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The standard deviation of the sampling distribution of the sample mean is $115,000. The population standard deviation was $25,00

Zina [86]

Answer:

0.31084

Step-by-step explanation:

When given a question where by a random sample is chosen for the population, the z score formula used =

z = (x-μ)/Standard error

where x is the raw score

μ is the population mean

Standard error = σ/√n,

σ is the population standard deviation

n = number of samples

For x = $114,000, μ = $115,000, σ = 25,000, n = 100

z = (x-μ)/Standard error

= z = (x-μ)/ σ/√n

z = 114,000 - 115,000/ 25,000/√100

= -1000/25,000/10

= -1000/2500

z = -0.4

Determining the probability value from Z-Table:

P(x = 114000) = P(z = -0.4)

= 0.34458

For x = $116,000, μ = $115,000, σ = 25,000, n = 100

z = (x-μ)/Standard error

= z = (x-μ)/ σ/√n

z = 116,000 - 115,000/ 25,000/√100

= 1000/25,000/10

= 1000/2500

= 0.4

Determining the Probability value from Z-Table:

P(x = 116000) = P(z = 0.4)

= 0.65542

The probability that the sample mean selling price was between $114,000 and $116,000 is calculated as

= P(114,000< x < 116,000)

= P(-Z<x<Z)

= P(-0.4<x< 0.4

= 0.65542 - 0.34458

= 0.31084

Therefore, the probability that the sample mean selling price was between $114,000 and $116,000 is 0.31084

5 0

3 years ago

What is 1/2 of 5 in fraction

qaws [65]

Answer:

5/2

Step-by-step explanation:

6 0

3 years ago

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The equation 26 plus 0.15 = c gives the cost c in dollars that a store charges to deliver an appliance that weighs p pounds. Use

Inessa [10]

It would weigh 140 pouds

4 0

3 years ago

HELPPPPPPPPPPPP!!!!!

kykrilka [37]

9=3^2

3^(2x)=(3^2)^(3x-4)
3^(2x)=3^(6x-8)
2x=6x-8
0=4x-8
8=4x
2=x

6 0

3 years ago

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34,000 people attended a ballgame at a stadium that offers two kind of seats: general admission and reserved. The day's receipts

hoa [83]

Answer:

The number of people who paid $ 12 for reserved seat is 5,000

The number of people who paid $ 4 for general seat is 29,000

Step-by-step explanation:

Given as :

The total number of people attending a ballgame = 34,000

The total receipt of the ticket's seat = $ 176,000

The amount pad for reserved seat = $ 12

The amount paid for general admission = $ 4

Let The number of people for reserved seat = r

And The number of people for general admission = g

Now, According to question

The total number of people attending a ballgame = The number of people for reserved seat + The number of people for general admission

or, r + g = 34,000 ...........1

The total receipt of the ticket's seat = The amount pad for reserved seat × The number of people for reserved seat + The amount paid for general admission × The number of people for general admission

Or, $ 12 × r + $ ×4 g = $ 176,000 .........2

or, $ 12 × ( r + g ) = $ 12 × 34000

Or, $ 12 r + $ 12 g = $ 408,000

Solving equation

( $ 12 r + $ 12 g ) - ($ 12 r + $ 4 g ) = $ 408,000 - $ 176,000

Or, ( $ 12 r - $ 12 r ) + ( $ 12 g - $ 4 g ) = $ 232,000

Or 0 + 8 g = 232,000

∴ g = $\frac{232000}{8}$

I.e g = 29,000

So , The number of people for general admission = g = 29,000

Put the value of g in Eq 1

I.e r + g = 34,000

or , r = 34,000 - g

∴ r = 34000 - 29000

I.e r = 5,000

So, The number of people for reserved seat = r = 5,000

Hence The number of people who paid $ 12 for reserved seat is 5,000

And The number of people who paid $ 4 for general seat is 29,000 Answer

6 0

3 years ago