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ANTONII [103]
3 years ago
15

How many natural numbers n satisfy the inequality: 1/7 < n/10 < 4/5 ?

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
7 0
ANSWER

Five natural numbers.

EXPLANATION

The given inequality is

\frac{1}{7}  \:  <  \:  \frac{n}{10} \:  <  \:  \frac{4}{5}

We multiply each term in the inequality by 10 to obtain,

\frac{1}{7} \times 10\:  <  \:  \frac{n}{10}  \times 10\:  <  \:  \frac{4}{5}  \times 10

This gives us,

\frac{10}{7}  \:  <  \:  n \:  <  \:  \frac{40}{5}

We simplify further to obtain,


1\frac{3}{7}  \:  <  \: n \:  <  \: 8

The natural numbers that satisfy the inequality are;


2,3,4,5,7


Hence 5 natural numbers satisfy the given inequality.
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