Answer:
Area of the bookmark = 52.56 cm²
Step-by-step explanation:
The two semicircles attached at both end of the rectangle will give us a full circle.
Therefore,
Area of the bookmark = area of rectangle + Area of a circle
Area of the bookmark = L × W + πr²
Length (L) = 10 cm
Width (W) = 4 cm
radius (r) = ½(4) = 2 cm
π = 3.14
Plug in the values into the equation
Area of bookmark = 10 × 4 + 3.14 × 2²
= 40 + 12.56
= 52.56 cm²
A
14
d=c/pi
45/pi=14
x=1 y=-5
7(5x-2y=15) ---> 35x-14y=105
2(7x+7y=-28) --> + <u>14x+14y=-56</u>
49x=49 --->x=1
5(1)-2y=15 ---> 5-2y=15 ---> -2y=10 ---> y=-5