Answer:
<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>
Step-by-step explanation:
First alloy contains 34% copper and the second alloy contains 48% alloy.
We wish to make 46 pounds of a third alloy containing 37% copper.
Let the weight of first alloy used be
in pounds and the weight of second alloy used be
in pounds.
Total weight =
![-(i)](https://tex.z-dn.net/?f=-%28i%29)
Total weight of copper = ![37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }](https://tex.z-dn.net/?f=37%5C%25%5Ctext%7B%20of%2046%20pounds%20%3D%20%7D34%5C%25%5Ctext%7B%20of%20%7Dx%5Ctext%7B%20pounds%20%2B%20%7D48%5C%25%5Ctext%7B%20of%20%7Dy%5Ctext%7B%20pounds%20%7D)
![-(ii)](https://tex.z-dn.net/?f=-%28ii%29)
Subtracting 34 times first equation from second equation,
![34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds](https://tex.z-dn.net/?f=34x%2B48y-34x-34y%3D1702-34%5Ctimes46%5C%5C14y%3D138%5C%5Cy%3D9.857%5Ctext%7B%20%7Dpounds%20%5C%5Cx%3D36.143%5Ctext%7B%20%7Dpounds)
∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.
They need look a median wieght.
Answer:
x = 2
Step-by-step explanation:
(16 =
and 8 =
)
![2^{12x} = 2^{3x+18}](https://tex.z-dn.net/?f=2%5E%7B12x%7D%20%3D%202%5E%7B3x%2B18%7D)
Since the base number is 2, the exponents must equal each other.
So:
12x = 3x+18
9x = 18
x = 2
Answer:
funny I have this question and I thought it was D