Find the derivative of the vector function r(t)=ta×(b+tc), where a=⟨2,−3,4⟩, b=⟨−4,5,−1⟩, and c=⟨−2,−1,5⟩.
1 answer:
Answer:
derivative of the vector function given = ( -16-22t, 14-36t, -2-16t )
Step-by-step explanation:
given data:
vector function : r(t) = ta*(b+tc)
a = ( 2,-3.4) . b = (-4,5,-1). c = ( -2,-1,5)
to find the derivative of the vector function we will differentiate with respect to x attached below is the detailed solution
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675 people will have score between 85 and 120
Step-by-step explanation:
Given
Mean = 100
SD = 15
If we have to find percentage of score between two values we have to find the z-score for both values and then area under the curve for both values
z-score is given by:
for a value x:
So,
For 85:
Now we have to find the area under the curve for both values of z-score. z-score tables are used for this purpose.
So,
For z1 : 0.1587
For z2: 0.9082
The area between z11 and z2:
So the probability of score between 85 and 120 is 0.7495
As the sample is of 900 people, the people with scores between 85 and 120 will be:
900*0.7495 = 674.55 people
Rounding off to nearest whole number
675 people will have score between 85 and 120
Keywords: Probability, SD
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