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Arlecino [84]
3 years ago
13

The length of a rectangle is 3 times the width. if the perimeter is to be greater than or equal to 104 meters. what are the poss

ible values for the width?
Mathematics
2 answers:
MAVERICK [17]3 years ago
4 0
X=width
3x=length
2x+2·3x≥104
8x≥104
x≥13
Naya [18.7K]3 years ago
3 0
Let L = length, W = width, and formula for perimeter (each side added) is
P = 2L + 2W

The first statement tells us L = 3W so we can substitute 3W for L in the formula.
P = 2(3W) + 2W

The 2nd statement tells us to make the expression for the perimeter into an inequality where it is ≥ (greater than or equal to) 104
2(3W) + 2W ≥ 104

We only need to solve this to find the possible values for W/  
2(3W) + 2W ≥ 104
8W ≥ 104    ← result of simplifying left side
W ≥ 13    ← result of dividing both sides by 8

ANSWER: The width is greater than or equal to 13: W ≥ 13

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