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maria [59]
3 years ago
12

What is the equation of a line that has a slope of 2 and passes through the point (4,6) ?

Mathematics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

y-6=2\,(x-4)

or in slope y-intercept form :

y=2x-2

Step-by-step explanation:

The easiest way of find the answer for this is to use what is called the "point-slope" form of a line, because you are in fact given the value of the slope (m) and also a point   (x_0,y_0)  it goes through:

y-y_0=m\,(x-x_0)

In our case the equation becomes:

y-y_0=m\,(x-x_0)\\y-6=2\,(x-4)\\

This can also be written in the slope-intercept form by solving for "y" and operating to remove the parenthesis:

y-6=2\,(x-4)\\y=2x-8+6\\y=2x-2

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Can someone please answer this, ill give you brainliest Would be very appreciated.
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Explanation:

f(x) = (x-4)(x+2)

1) For x-intercept, y will be 0

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  • (x-4) =0, (x+2) = 0
  • x = 4, x = -2

<u />

<u>x-intercept</u>: (4, 0), (-2, 0)

2) For vertex: x = -b/2a where ax² + bx + c

<u>Quadratic function</u>:

  • (x-4)(x+2)
  • x² +2x-4x -8
  • x² -2x -8

<u>vertex</u>:

  • x = -(-2)/2(1)
  • x = 1

y: (x-4)(x+2) = (1-4)(1+2) = -9

ordered pair of vertex: (1, -9)

3) For y-intercept, x will be 0

  • (x-4)(x+2)
  • (0-4)(0+2)
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<u>y-intercept</u>: (0, -8)

8 0
2 years ago
Read 2 more answers
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