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maria [59]
3 years ago
12

What is the equation of a line that has a slope of 2 and passes through the point (4,6) ?

Mathematics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

y-6=2\,(x-4)

or in slope y-intercept form :

y=2x-2

Step-by-step explanation:

The easiest way of find the answer for this is to use what is called the "point-slope" form of a line, because you are in fact given the value of the slope (m) and also a point   (x_0,y_0)  it goes through:

y-y_0=m\,(x-x_0)

In our case the equation becomes:

y-y_0=m\,(x-x_0)\\y-6=2\,(x-4)\\

This can also be written in the slope-intercept form by solving for "y" and operating to remove the parenthesis:

y-6=2\,(x-4)\\y=2x-8+6\\y=2x-2

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AC is diagonal of square ABCD, and the length of AC is 4. What is the area of the square?
dybincka [34]
Option d.
as we know the corner of a square is always 90°. So we can apply that (side of the square)^2+(side of the square)^2 = (diagonal of the side)^2

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3 years ago
The perimeter of a square is 32 centimeters. What is the length of one side?
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6 0
3 years ago
The vertices of quadrilateral MNPQ are M(−3,−2),N(−1,4),P(2,4), and Q(4,−2). Translate quadrilateral MNPQ using the vector ⟨3,−4
muminat

Answer:

see explanation

Step-by-step explanation:

A translation using the vector < 3, - 4 > , means

Add 3 to the x- coordinate and subtract 4 from the y- coordinate, so

M (- 3, - 2 ) → M' (- 3 + 3, - 2 - 4 ) → M' (0, - 6 )

N (- 1, 4 ) → N' (- 1 + 3, 4 - 4 ) → N' (2, 0 )

P (2, 4 ) → P' (2 + 3, 4 - 4 ) → P' (5, 0 )

Q (4, - 2 ) → Q' (4 + 3, - 2 - 4 ) → (7, - 6 )

4 0
3 years ago
Ameekah is working with consecutive integers
Irina-Kira [14]

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As we can see it's the latest plus 1

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x, x + 1, x + 1 + 1, x + 1 + 1 + 1

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So it's x + 1.

7 0
3 years ago
Read 2 more answers
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