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MatroZZZ [7]
3 years ago
15

What 11 % is of 25 and how did you get the answer

Mathematics
1 answer:
dimaraw [331]3 years ago
3 0
The answer is 44%
hoped i helped 
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(Angle relationships) Solve this question
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3 years ago
For what values of x'is x2 + 2x = 24 true?
Paladinen [302]

Answer:

\boxed{Values \: true \: of \: 'x' \: for \: equation \: {x}^{2} + 2x = 24 \: is \: -6 \: and \: 4}

Step-by-step explanation:

=  >  {x}^{2}  + 2x = 24 \\  \\  =  >  {x}^{2}  + 2x - 24 = 0 \\  \\  =  >  {x}^{2}  + (6 - 4)x - 24 = 0 \\  \\  =  >  {x}^{2}  + 6x - 4x  -  24 = 0 \\  \\  =  > x(x + 6) - 4(x + 6) = 0 \\  \\  =  > (x + 6)(x - 4) = 0 \\  \\  =  > x + 6 = 0 \:  \:  \:  \:  \:  \:  \:  \: and \:  \:  \:  \:  \:  \:  \:  \:  \: x - 4 = 0 \\  \\  =  > x =  - 6 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: and \:  \:  \:  \:  \:  \:  \:  \:  \: x = 4

Values true of 'x' for equation x² + 2x = 24 is -6 and 4

7 0
4 years ago
A.Find a formula for
Vlada [557]

a. Notice that

1/(1*2) = 1/2 = 1 - 1/2

1/(2*3) = 1/6 = 1/2 - 1/3

1/(3*4) = 1/12 = 1/3 - 1/4

and so on, which suggests the n-th term of the sum can be written as

\dfrac1{n(n+1)}=\dfrac1n-\dfrac1{n+1}

Then the sum itself is telescoping:

\dfrac1{1\cdot2}+\dfrac1{2\cdot3}+\dfrac1{3\cdot4}+\cdots+\dfrac1{n(n+1)}

=\left(1-\dfrac12\right)+\left(\dfrac12-\dfrac13\right)+\left(\dfrac13-\dfrac14\right)+\cdots+\left(\dfrac1n-\dfrac1{n+1}\right)

=1-\dfrac1{n+1}

b. The proof is trivial:

\dfrac1n-\dfrac1{n+1}=\dfrac{n+1}{n(n+1)}-\dfrac n{n(n+1)}=\dfrac{n+1-n}{n(n+1)}=\dfrac n{n+1}

so the formula found in (a) is correct.

5 0
3 years ago
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