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Nady [450]
3 years ago
15

Joshua took a total of 12 "i-Ready" quizzes over the course of 2 weeks. How many weeks of school will Joshua have to attend this

quarter before he have taken a total of 18 quizzes? Solve using unit rates.
Mathematics
1 answer:
Sergio039 [100]3 years ago
7 0
I think the answer is 2 weeks 6 days because if over the course of 2 weeks they took 12 I ready quizzes  the he needs 18 quizzes and it leaves 1 day extra
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what is the area of a regular pentagon with sides of length 13 and an apothem of length 8.95, in square units
Assoli18 [71]
The area is 290.760680699535.
3 0
3 years ago
In a class of 20 students ,40% are boys.25% of theboys and 50% of the girls were glasses.how many students were glassses. show w
Mice21 [21]
40% of 20 is 8 Boys
60% of 20 is 12 Girls
50% of the Girls is 6
25% of the Boys is 2
6 + 2 = 8 Students wore glasses

Hope this helps!
4 0
3 years ago
What do you know about the side lengths and trigonometric ratios in special right triangles
TEA [102]

Explanation:

This looks like an essay question with no right answer.

__

There are two "special" right triangles:

  isosceles 45°-45°-90° triangle with sides in the ratios 1 : 1 : √2

  30°-60°-90° triangle with sides in the ratios 1 : √3 : 2

These side lengths give rise to the trigonometric ratios shown below for angles with 30°, 45°, or 60° as reference angles.

6 0
3 years ago
HELP ME PLZ!!!!!!!!       Find the solution of this system of equations.
Strike441 [17]
Set equal to each other since both equal 90

5x-6y=-10x-6y
add 6y to both sides
5x=-10x
x=0


5(0)-6y=-90
-6y=90
divide by -6
y=-15

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7 0
3 years ago
On the unit circle, which of the following angles has the terminal point coordinates (√2/2,-√2/2)
aleksandr82 [10.1K]

Answer:

Option B

Step-by-step explanation:

A unit circle means radius of the circle = 1 unit

Let a terminal point on the circle is (x, y) and angle between the point P and x-axis is θ.

Center of the circle is origin (0, 0).

Therefore, ordered pair representing the terminal point will be (OP×Cosθ, OP×Sinθ) = (\frac{\sqrt{2} }{2},-\frac{\sqrt{2} }{2})

OP.Cosθ = 1×Cosθ = \frac{1}{\sqrt{2}}

Cosθ = \frac{1}{\sqrt{2}}

θ = \frac{\pi }{4}+2\pi n,  \frac{7\pi }{4}+2\pi n where n = integers

Similarly, OP×Sinθ = 1×Sinθ = -\frac{1}{\sqrt{2}}

Sinθ = -\frac{1}{\sqrt{2} }

θ = \frac{5\pi }{4}+2\pi n,  \frac{7\pi }{4}+2\pi n where n = integer

Common value of θ will be, θ = \frac{7\pi }{4}

Option B will be the answer.

5 0
3 years ago
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