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-Dominant- [34]
3 years ago
6

Is it possible to build a triangle with side lengths of 3, 3, and 9?

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
5 0

answer:

no

step-by-step explanation:

each side must be smaller than the sum of other sides

so

9+3>3-right

3+3<9-wrong

Olenka [21]3 years ago
4 0

Answer:

N0

Step-by-step explanation:

The sides of a triangle must be

a-b< c< a+b  where a and b are the two smaller sides and c is the larger side

3-3 <9< 3+3

0<9<6

This is not true so it cannot make a triangle

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A shop sells stuffed animals. The sales team calculated that today's bear sales were 5 more than 5/4ths the number of all
slega [8]

Answer:

25

Step-by-step explanation:

25-5=20, 5/4*20=25

3 0
3 years ago
For which equation is y = 7 a solution?
Natasha2012 [34]

Answer:B

Step-by-step explanation:

y - 26 = -19

y + 26 - 26 = -19 + 26

y=7

4 0
3 years ago
Read 2 more answers
What additional information would you need to prove by the HL theorem?
Butoxors [25]

Answer:

<em>Answer:</em> <em>A</em>   \overline{TM}\cong \overline{OR}

Step-by-step explanation:

The HL Theorem states that if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent.

Triangles TRO and OMT share the hypotenuse, so the first part of the theorem is met.

Both triangles are right because they have an internal angle of 90°, so the second condition is also met.

Since there is no indication of any leg to be congruent to another leg, we need additional information to prove that both triangles are congruent.

One of these two conditions should be met:

Side TM is congruent to side OR, or

Side MO is congruent to side RT.

From the available options, only the first is correct.

Answer: A \mathbf{\overline{TM}\cong \overline{OR}}

8 0
3 years ago
Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De
Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.

The random variable <em>X</em> is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is,\lambda=\frac{1}{\mu}=\frac{1}{7}.

The probability density function of <em>X</em> is:

f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx

                      =\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0
3 years ago
your basketball team made 10 three pointers 8 two pointers and 12 one point foul shots your openents made 8 three pointers 12 tw
inn [45]

Answer:

The opponents won by 1 points

Step-by-step explanation:

Your team (10*3)+(8*2)+(12*1)=58

Opponents (8*3)+(12*2)+(11*1)=59

8 0
3 years ago
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