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3 years ago

Please solvex^2+x-6006=0

Mathematics

1 answer:

Ratling [72]3 years ago

7 0

Step-by-step explanation:

x^2+x-6006=0

x^2+78x-77x-6006=0

x(x+78)-77(x+78)=0

(x-77)(x+78)=0

=>x=77 or x=78

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The net worthw(t) of a company is growing at a rate of′(t) = 2000−121t2dollarsper year, wheretis in years since 1990.(a) If the

stiv31 [10]

Answer:

The worth of the company in 2000 is $56,000.

Step-by-step explanation:

The growth rate of the company is:

$f'(t)=2000-12t^{2}$

To determine the worth of the company in 2000, first compute the change in the net worth during the period 1990 (t = 0) to 2000 (t = 10) as follows:

$\int\limits^{10}_{0} {2000-12t^{2}} \, dt =\int\limits^{10}_{0} {2000} \, dt-12\int\limits^{10}_{0} {t^{2}} \, dt=2000 |t|^{10}_{0}-12|\frac{t^{3}}{3}|^{10}_{0}\\=(2000\times10)-(4\times10^{3})\\=20000-4000\\=16000$

The increase in the company's net worth from 1990 to 2000 is $16,000.

If the company's worth was $40,000 in 1990 then the worth of the company in 2000 is:

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2 years ago

Simplify by using distributive property 3+11(2c+3)

lidiya [134]

Answer:

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Step-by-step explanation:

3+11(2c+3)

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2 years ago

Please solvex^2+x-6006=0​

Please solvex^2+x-6006=0