3/8= 0.375
+1/2= 0.50
------------------
=0.875
F(x)=x^2+6x-2, vertex: (-3, -11)
First, put -(6)/2(1) or -b/2a.
You then get -3 as the X value of the vertex.
Next, insert -3 back into the equation to get the Y value of the vertex.
(-3)^2+6(-3)-2 = -11
You then have -11 as the Y value of the vertex.
<h3>
Answer: C) incenter</h3>
========================================
Explanation:
If you were to intersect the angle bisectors (at least two of them), then you would locate the incenter. The incenter is the center of the incircle which is a circle where it is as large as possible, but does not spill over and outside the triangle. Therefore this circle fits snugly inside the triangle.
--------------
extra notes:
* The centroid is found by intersecting at least two median lines
* The circumcenter is found by intersecting at least two perpendicular bisector lines
* The orthocenter is found by intersecting at least two altitude lines
* The incenter is always inside the triangle; hence the "in" as part of the name. The centroid shares this property as well because the medians are completely contained within any triangle. The other two centers aren't always guaranteed to be inside the triangle.
* The red lines cut each angle of the triangle into two equal or congruent pieces.
Depends on how much the quiz of your class are worth. The quizzes could represent only %50 of your grade and the rest might be homework
Answer:
A and C.
Step-by-step explanation:
to get rid of the square root & n, you would have to multiply it by n on both sides of the equation, giving you r^n=a.
also to get rid of the square root & n, you can also multiply both sides of a and r by the exponential fraction with n as the denominator:
![\sqrt[n]{a} =r \\(a)^\frac{1}{n} = r\\a\frac{1}{n} = r](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%3Dr%20%5C%5C%28a%29%5E%5Cfrac%7B1%7D%7Bn%7D%20%3D%20r%5C%5Ca%5Cfrac%7B1%7D%7Bn%7D%20%3D%20r)
