Question

Please help! Thank youuuu!

Answer 1

F(x) = 3x² + 6x - 1

The graph is a parabola open upward (a= 3>0) with a minimum.

Calculate the vertex:

x = -b/2a → x = -6/(2.3) = -1. Then the axis of symmetry is x = - 1
Now to calculate the minimum, plugin the value of x:

y = 3x² + 6x - 1

y = 3(-1)² + 6(-1) -1

y= 3 - 6 -1 and y = - 4,

Ten the vertex (minimum) is at (-1,- 4)