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3 years ago

What is the least number of 4 digits which is divided by 12 ,15,20 and 35?

2 answers:

4 0

Here, First of all, you need to calculate the LCM of 12, 15, 20 & 35
LCM of 12, 15, 20 & 35 is 420

Now, We know, smallest 4-digit number is 1000,
Divide, 420 from 1000, It cuts on 840 (with quotient 2),

So, we need next term, in order to know, just add another 420 to 840, which is:
840 + 420 = 1260

In short, Your Answer would be 1260

Hope this helps!

nalin [4]3 years ago

3 0

Get the primes for each number

12 = 2*2*3
15 = 3*5
20 = 2*2*5
35 = 5*7

So 2*2*3*5*7 = 420 , but we want the least 4-digit number =>
420*3 = 1260

The searched number is 1260
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Answer:

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Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

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3 years ago

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polet [3.4K]

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2 years ago

Read 2 more answers

Point P'P

Snowcat [4.5K]

<u>Given</u>:

The point P' is the image of the point P under the translation $(x,y) \implies (x-6, y-1)$

The coordinates of the point P are (6,0)

We need to determine the coordinates of the point P'

<u>Coordinates of the point P':</u>

The coordinates of the point P' can be determined by substituting the coordinates of the point P(6,0) in the translation.

Thus, substituting the coordinates, we have;

$(6,0)\implies (6-6,0-1)$

Simplifying the coordinates, we get;

$(6,0)\implies (0,-1)$

Thus, the coordinates of the point P' is (0,-1)

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