What is the least number of 4 digits which is divided by 12 ,15,20 and 35?

2 answers:

4 0

Here, First of all, you need to calculate the LCM of 12, 15, 20 & 35
LCM of 12, 15, 20 & 35 is 420

Now, We know, smallest 4-digit number is 1000,
Divide, 420 from 1000, It cuts on 840 (with quotient 2),

So, we need next term, in order to know, just add another 420 to 840, which is:
840 + 420 = 1260

In short, Your Answer would be 1260

Hope this helps!

nalin [4]3 years ago

3 0

Get the primes for each number

12 = 2*2*3
15 = 3*5
20 = 2*2*5
35 = 5*7

So 2*2*3*5*7 = 420 , but we want the least 4-digit number =>
420*3 = 1260

The searched number is 1260
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Given population proportion was estimated to be 0.3

p = 0.3

Given maximum of error E = 0.04

we know that maximum error

$M.E = \frac{Z_{\alpha } \sqrt{p(1-p)} }{\sqrt{n} }$

The 85% confidence level $z_{\alpha } = 1.44$

$\sqrt{n} = \frac{Z_{\alpha } \sqrt{p(1-p)} }{m.E}$

$\sqrt{n} = \frac{1.44X\sqrt{0.3(1-0.3} }{0.04}$

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now squaring on both sides n = 190.44

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<u>Conclusion</u>:-

Hence The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

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