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3 years ago

What is the least number of 4 digits which is divided by 12 ,15,20 and 35?

2 answers:

4 0

Here, First of all, you need to calculate the LCM of 12, 15, 20 & 35
LCM of 12, 15, 20 & 35 is 420

Now, We know, smallest 4-digit number is 1000,
Divide, 420 from 1000, It cuts on 840 (with quotient 2),

So, we need next term, in order to know, just add another 420 to 840, which is:
840 + 420 = 1260

In short, Your Answer would be 1260

Hope this helps!

nalin [4]3 years ago

3 0

Get the primes for each number

12 = 2*2*3
15 = 3*5
20 = 2*2*5
35 = 5*7

So 2*2*3*5*7 = 420 , but we want the least 4-digit number =>
420*3 = 1260

The searched number is 1260
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3 years ago

A dog jumps straight up in the air to catch a ball and lands on the ground 1.3 s later. Let h(t) represent the dog’s height, in

slamgirl [31]

The given question have mistake. The correct question is written below.

Question:

A dog jumps straight up in the air to catch a ball and lands on the ground 6.37 s later. Let h(t) represent the dog’s height, in meters, t seconds after he leaves the ground. Which equation models the dog’s height for a given time t?

Answer:

Option B:

$h(t)=-4.9 t^{2}+6.37t$

Solution:

<u>General formula for the height of the projectile over time:</u>

(1) $h(t)=-16 t^{2}+v t+s$

Where h = height in feet, t = time, v = initial velocity and s = initial height (feet)

(2) $h(t)=-4.9 t^{2}+v t+s$

Where h = height in meters, t = time, v = initial velocity and s = initial height(meter)

Given initial velocity = 6.37 s and initial height is 0.

The height of the dog is in meters.

So, use second formula and substitute v = 6.37 and s = 0.

$h(t)=-4.9 t^{2}+v t+s$

$h(t)=-4.9 t^{2}+6.37t+0$

$h(t)=-4.9 t^{2}+6.37t$

Hence option B is the correct answer.

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3 years ago