You can see how this works by thinking through what's going on.
In the first year the population declines by 3%. So the population at the end of the first year is the starting population (1200) minus the decline: 1200 minus 3% of 1200. 3% of 1200 is the same as .03 * 1200. So the population at the end of the first year is 1200 - .03 * 1200. That can be written as 1200 * (1 - .03), or 1200 * 0.97
What about the second year? The population starts at 1200 * 0.97. It declines by 3% again. But 3% of what??? The decline is based on the population at the beginning of the year, NOT based no the original population. So the decline in the second year is 0.03 * (1200 * 0.97). And just as in the first year, the population at the end of the second year is the population at the beginning of the second year minus the decline in the second year. So that's 1200 * 0.97 - 0.03 * (1200 * 0.97), which is equal to 1200 * 0.97 (1 - 0.03) = 1200 * 0.97 * 0.97 = 1200 * 0.972.
So there's a pattern. If you worked out the third year, you'd see that the population ends up as 1200 * 0.973, and it would keep going like that.
So the population after x years is 1200 * 0.97x
C.Quadrilateral is the answer for the following because rhombus, trapezoid, isosceles trapezoid have parallel sides.
Answer:
5x^2+120x
Step-by-step explanation:
5x(x+24)
Step 1: Use distributive property to expand the expression. Multiply 5x separately with all the terms inside the bracket.
Step 2: 5x(x) = 5x^2
5x(24) = 120x
Answer: 5x^2+120x
Note: If you need to further solve it, you can factor it.
To Factor;
5x^2+120x
Step 1: Factor out the common: 5x
Step 2: 5x times x = x^2
5x times 24 = 120x
Therefore,
Factored answer: 5x(x+24)
Hope this helps.
Answer:
n is the least value, q is the greatest value and q is also the closest to zero
Step-by-step explanation:
