Step 
<u>Find the irreducible fraction in each ratio</u>
<u>case 1)</u> 
Divide by
boths numerator and denominator

<u>case 2)</u> 
Divide by
boths numerator and denominator

<u>case 3)</u> 
Divide by
boths numerator and denominator

<u>case 4)</u> 
Divide by
boths numerator and denominator

<u>case 5)</u> 
Divide by
boths numerator and denominator

<u>case 6)</u> 
Divide by
boths numerator and denominator

<u>case 7)</u> 
Divide by
boths numerator and denominator

<u>case 8)</u> 
Divide by
boths numerator and denominator

<u>case 9)</u> 
Divide by
boths numerator and denominator

<u>case 10)</u> 
Divide by
boths numerator and denominator

<u>case 11)</u> 
Divide by
boths numerator and denominator

<u>case 12)</u> 
Divide by
boths numerator and denominator

Step 
<u>Sort the ratios into bins</u>
1<u>) First Bin</u>
<u>
</u>



<u>2) Second Bin </u>
<u>
</u>


<u>3) Third Bin</u>



4<u>) Fourth Bin</u>
<u>
</u>




Answer:
x=8=2=3
Step-by-step explanation:
Please explain what the gap between the 7 and the 4 is, because I'm sure it's not 74x?
Either way, it looks like a linear graph, in which case yes, the range is going to be y∈<span>ℝ. Therefore, it's false, as it's for ALL real values of y, including negative values.</span>
Answer:
9a-13b
Step-by-step explanation:
6a-12b+3a-b
=6a+3a-12b-b
=9a-13b
Answer:
Step-by-step explanation:
What we know about this, or should know about this, is that the diagonals bisect each other. That means that
x = y + 2 and y + 10 = 2x - 8
Because the first equation is already solved for x, sub that value into the second equation in place of x to get:
y + 10 = 2(y + 2) - 8 and
y + 10 = 2y + 4 - 8 and
y + 10 = 2y - 4 so
y = 14.
Back sub that in to solve for x:
If x = y + 2 and y = 14, then
x = 16