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Amanda [17]
3 years ago
11

I need ONLY number 7 my teacher gave me this packet and i can’t figure that one out

Mathematics
2 answers:
Trava [24]3 years ago
8 0
Answer:

(3x+6)^2

Hope you finished the packet and got a good grade on it!!
klemol [59]3 years ago
5 0

Answer:

(3x+6)^2

Step-by-step explanation:

the side of the inner square is 3x long

to have the wider square side we must add 3 two times, so 3x + 3 + 3 = 3x+6

to find the area we must square it (3x+6)^2

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tangare [24]

Answer:

why they're so helpful

Step-by-step explanation:

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3 years ago
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In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
I need help with all of it ...
erastovalidia [21]
1)
36/3 x 42/3 = 12yd x 14yd

12×14=168

you will need 168 square yards to recarpet the kindergarten.


2)
168×24.99=4198.32

it will cost $4198.32 to recarpet the kindergarten.


3)
3.5 is 35% of 10

4198.32÷3.5=1198.52

they will need to sell 1199 coupon books to completely pay for the the recarpeting.
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What are the first 15 numbers of pi
kupik [55]
The first 15 letter of PI, are! <span>3.1415926535897 Hope this helps. </span>
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How many solutions does the following system have 3x+2y=1 -9x-6y=3
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Since there are 2 variables there will be 2 answers.
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