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maks197457 [2]
2 years ago
11

Any help is useful Equilateral triangle with a side of 16mm and was 155 mm long

Mathematics
1 answer:
zmey [24]2 years ago
5 0

Answer:

Step-by-step explanation:

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A fair coin is flipped eight times. What is the probability of the coin landing heads up exactly 2 times?
dimulka [17.4K]

Answer:

50%

Step-by-step explanation:

no matter how many times it is flip you will get heads or tails.

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3 years ago
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Wilhema bought 6 bars of soap for $12. The next day, Sophia bought 10 bars of the same kind of soap for $20. What is the cost of
kaheart [24]

Answer:

$2

Step-by-step explanation:

To get this number you can divide the cost by the amount of bars of soap.

12/6=2

20/10=2

Hope this helps!


8 0
3 years ago
5,000 is invested at an interest rate of 8% compounded annually. how much is the investment return after 20 years?​
iren [92.7K]

Step-by-step explanation:

5k×8×20

_______ =800

100

6 0
2 years ago
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Simplify:<br> (4p3 + 6p2 – 7) – (8p? – 7 – 3p)
Kipish [7]

Answer:

4p3 + 6p2 - 8p - 7

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "p2"   was replaced by   "p^2".  1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

 (((4 • (p3)) +  (2•3p2)) -  7) -  8p

STEP

2

:

Equation at the end of step

2

:

 ((22p3 +  (2•3p2)) -  7) -  8p

STEP

3

:

Checking for a perfect cube

3.1    4p3+6p2-8p-7  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  4p3+6p2-8p-7

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -8p-7

Group 2:  4p3+6p2

Pull out from each group separately :

Group 1:   (8p+7) • (-1)

Group 2:   (2p+3) • (2p2)

3.3    Find roots (zeroes) of :       F(p) = 4p3+6p2-8p-7

Polynomial Roots Calculator is a set of methods aimed at finding values of  p  for which   F(p)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  p  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  4  and the Trailing Constant is  -7.

The factor(s) are:

of the Leading Coefficient :  1,2 ,4

of the Trailing Constant :  1 ,7

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        3.00    

     -1       2        -0.50        -2.00    

     -1       4        -0.25        -4.69    

     -7       1        -7.00       -1029.00    

     -7       2        -3.50        -77.00    

     -7       4        -1.75        3.94    

     1       1        1.00        -5.00    

     1       2        0.50        -9.00    

     1       4        0.25        -8.56    

     7       1        7.00        1603.00    

     7       2        3.50        210.00    

     7       4        1.75        18.81    

Final result :

 4p3 + 6p2 - 8p - 7

5 0
2 years ago
Pls help this is pretty urgent
KIM [24]

Answer:

(a)  0

(b)  f(x) = g(x)

(c)  See below.

Step-by-step explanation:

Given rational function:

f(x)=\dfrac{x^2+2x+1}{x^2-1}

<u>Part (a)</u>

Factor the <u>numerator</u> and <u>denominator</u> of the given rational function:

\begin{aligned} \implies f(x) & = \dfrac{x^2+2x+1}{x^2-1} \\\\& = \dfrac{(x+1)^2}{(x+1)(x-1)}\\\\& = \dfrac{x+1}{x-1}\end{aligned}

Substitute x = -1 to find the limit:

\displaystyle \lim_{x \to -1}f(x)=\dfrac{-1+1}{-1-1}=\dfrac{0}{-2}=0

Therefore:

\displaystyle \lim_{x \to -1}f(x)=0

<u>Part (b)</u>

From part (a), we can see that the simplified function f(x) is the same as the given function g(x).  Therefore, f(x) = g(x).

<u>Part (c)</u>

As x = 1 is approached from the right side of 1, the numerator of the function is positive and approaches 2 whilst the denominator of the function is positive and gets smaller and smaller (approaching zero).  Therefore, the quotient approaches infinity.

\displaystyle \lim_{x \to 1^+} f(x)=\dfrac{\to 2^+}{\to 0^+}=\infty

5 0
1 year ago
Read 2 more answers
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