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alisha [4.7K]
3 years ago
6

What is the converse of the statement “If an angle is a right angle, then it measures 90 degrees”? ...?

Mathematics
1 answer:
GREYUIT [131]3 years ago
3 0
A converse statement is a statement that means, if B is equal to A, then A is equal to B. Based on this theory, the converse of the statement given in the question has to be written. "If an angle measures 90 degrees, then it is a right angle". I hope that this is the answer that has actually come to your help. 
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Which of the following is not a kind of consumer credit? a. installment credit b. personal loans c. service credit d. marginal c
Nat2105 [25]
A) installment credit
B ) personal loan
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service credit
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7 0
4 years ago
Read 2 more answers
6.
joja [24]

Answer:

x² - 16

Step-by-step explanation:

Given

(x - 4)(x + 4)

Each term in the second factor is multiplied by each term in the first factor, that is

x(x + 4) - 4(x + 4) ← distribute both parenthesis

= x² + 4x - 4x - 16 ← collect like terms

= x² - 16

6 0
4 years ago
What is the coefficient in this expression? <br> 17 + 5a
babymother [125]
The answer is the a next to the 5
4 0
4 years ago
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What is seventy-nine divided by twenty-five.
Elodia [21]
3.16 is the correct answer
4 0
3 years ago
Read 2 more answers
PLEASE HELP.
krek1111 [17]

Answer:

Part a) The radii are segments AC and AD and the tangents are the segments CE and DE

Part b) DE=4\sqrt{10}\ cm

Step-by-step explanation:

Part a)

we know that

A <u>radius</u> is a line from any point on the circumference to the center of the circle

A <u>tangent</u> to a circle is a straight line which touches the circle at only one point. The tangent to a circle is perpendicular to the radius at the point of tangency.

In this problem

The radii are the segments AC and AD

The tangents are the segments CE and DE

Part b)

we know that

radius AC is perpendicular to the tangent CE

radius AD is perpendicular to the tangent DE

CE=DE

Triangle ACE is congruent with triangle ADE

Applying the Pythagoras Theorem

AE^{2}=AC^{2}+CE^{2}

substitute the values and solve for CE

14^{2}=6^{2}+CE^{2}

CE^{2}=14^{2}-6^{2}

CE^{2}=160

CE=\sqrt{160}\ cm

CE=4\sqrt{10}\ cm

remember that

CE=DE

so

DE=4\sqrt{10}\ cm

7 0
3 years ago
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