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lara [203]
3 years ago
11

--(4+h) = 3h What is H

Mathematics
1 answer:
butalik [34]3 years ago
7 0
H= -1

Distribute:

-(4+h)= -4 - h

-4 - h= 3h

-4 +h = 3h + h

-4= 4h

-1 = h
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What is the greatest common factor of 48, 24, and 32?
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Answer:

8

Step-by-step explanation:

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The measure of two adjacent sides of a rectangle is in the ratio of 11:10. If the perimeter of the rectangle is 84 cm, then find
anygoal [31]
A ratio of 11x to 10x

Where x is a number to keep the ratio the same.

Perimeter = 84

Perimeter = 2 (Length + breadth)

84 = 2 ( 11x + 10x)
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x=2

So that means the actual length of the sides would be:

11 x 2 : 10 x 2
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So that means the length can be 22, and the breadth will be 20.
Or the length is 20, and the breadth is 22.

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4 years ago
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If you put 1/5, 2/3, and 5/8 from least to greatest what are they in order
Volgvan
It would be 1/5, 5/8, 2/3 because 1/5 is 24/120, 2/3 is 80/125, and 5/8 is 75/120
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3 years ago
Matt thinks that he has a special relationship with the number 4. In particular, Matt thinks that he would roll a 4 with a fair
Ahat [919]

Answer:

Step-by-step explanation:

Matt thinks that he has a special relationship with the number 2. In particular, Matt thinks that he would roll a 2 with a fair 6-sided die more often than you'd expect by chance alone. Suppose p is the true proportion of the time Matt will roll a 2.

(a) State the null and alternative hypotheses for testing Matt's claim. (Type the symbol "p" for the population proportion, whichever symbols you need of "<", ">", "=", "not =" and express any values as a fraction e.g. p = 1/3)

H0 =  

Ha =

(b) Now suppose Matt makes n = 46 rolls, and a 2 comes up 10 times out of the 46 rolls. Determine the P-value of the test:

P-value = ( u figure it out) u got it

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3 years ago
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QveST [7]

Answer:

The roots are

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x=\frac{1}{6} [3- i\sqrt{3}]

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we have

3x^2-3x+1

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

3x^2-3x+1=0  

so

a=3\\b=-3\\c=1

substitute in the formula

x=\frac{-(-3)\pm\sqrt{-3^{2}-4(3)(1)}} {2(3)}

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Remember that

i=\sqrt{-1}

so

x=\frac{1}{6} [3\pm i\sqrt{3}]

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x=\frac{1}{6} [3+ i\sqrt{3}]

x=\frac{1}{6} [3- i\sqrt{3}]

6 0
3 years ago
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