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4 years ago

What is the maximum value that the graph of y = cosx assumes?

1 answer:

7 0

Think about the unit circle. It has a radius of 1 and is centered about the origin. So the minimum value for cos(x) is -1.

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Miguel completed 24 out of 30 problems on his math test. Which represents the part of the math test Miguel completed?

r-ruslan [8.4K]

Answer:

The 24

Step-by-step explanation:

The 30 represents how many problems there were in all

Hope I was Helpful!!

Ohhhhh No wait the answer is . 80 Im so sorry

8 0

3 years ago

Read 2 more answers

ZA and ZB are supplementary angles. If mA = (2x − 9)º and m

Papessa [141]

angle A = 30

(2x-9) = (2x+21)
+9 +9
2x=2x+30

-2x -2x

=30

6 0

1 year ago

Fill in the blank to make the two fractions equivalent.<br> 4/5= ?/25

insens350 [35]

Answer:

20.00

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Graph abc and its image after a rotation of 180 about the origin

nikitadnepr [17]

This should be what you need, sorry for the wonky lines.

3 0

4 years ago

The number of chocolate chips in an 18-ounce bag of Chips Ahoy! chocolate chip cookies is approximately normally distributed wit

sineoko [7]

Answer:

a) 0.013

b) 0.7

c) 0.866

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1262

Standard Deviation, σ = 118

We are given that the distribution of number of chocolate chips is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(fewer than 1000 chocolate chips)

P(x < 1000)

$P( x < 1000) = P( z < \displaystyle\frac{1000 - 1262}{118}) = P(z < -2.220)$

Calculation the value from standard normal z table, we have,

$P(x < 1000) = 0.013 = 1.3\%$

b) P(contains more than 1200 chocolate chips)

$P(x > 1200) = P(z > \displaystyle\frac{1200-1262}{118}) = P(z > -0.5254)\\\\P( z > -0.5254) = 1 - P(z \leq -0.5254)$

Calculating the value from the standard normal table we have,

$1 - 0.300 = 0.7 = 70\%\\P( x > 1200) = 0.7$

c)P(contains between 1000 and 1400 chocolate chips)

$P(1000 \leq x \leq 1400) = P(\displaystyle\frac{1000 - 1262}{118} \leq z \leq \displaystyle\frac{1400-1262}{118}) = P(-2.22 \leq z \leq 1.169)\\\\= P(z \leq 1.169) - P(z < -2.22)\\= 0.879 - 0.013 = 0.866 = 86.6\%$

$P(1000 \leq x \leq 1400) = 86.6\%$

6 0

3 years ago