Please click on the photo aboveits difficult for me

Mathematics

2 answers:

LenKa [72]2 years ago

7 0

Answer:

H. 5.89 × 10⁻⁷

Step-by-step explanation:

F and I are not correct since F creates a negative number and I creates a large number.

You have to see how many digits you have to move the decimal point to get from the current number to 5.89 (in scientific notation, there is exactly one digit before the decimal point, regardless of rounding), which you've done, and should've gotten 7 points. So your answer would be H. 5.89 × 10⁻⁷.

Mashutka [201]2 years ago

4 0

Yes I sure can submit it

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If the sum of 4040 consecutive integer numbers is 2020, find out the absolute difference between the first number and the last n

bearhunter [10]

Let $x$ be the smallest of the consecutive integers summing to 2020. Then the largest integer in the sum is $x+4039,$ so our answer is $\boxed{4039}.$

For completeness, though, let's solve for the value of $x$ that satisfies the conditions of the problem. Recall that the sum of an arithmetic series with first term $a_1,$ last term $a_n,$ and $n$ terms, is $\frac{n(a_1+a_n)}{2}.$ Plugging in our known values gives us the equation $\frac{4040(2x+4039)}{2}=2020,$ which simplifies to $2x+4039=1.$ Thus, $x=-2019,$ so the 4040 consecutive integers are $-2019,-2018,\dots,-1,0,1,\dots,2018,2019,2020.$ Notice how everything except the $2020$ cancels out!