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Bezzdna [24]
3 years ago
11

What is 8% of 200? 25 4 16 8

Mathematics
2 answers:
Mashcka [7]3 years ago
6 0

Answer:

16

Step-by-step explanation:

Please mark brainliest!

sergiy2304 [10]3 years ago
5 0
The answer would be 16
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Which of the following is a solution of x2 + 2x + 4?
ivolga24 [154]
Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:

</span>x^2 + 2x + 4= 0.  "Completing the square" seems to be the easiest way to go here:

rewrite   x^2 + 2x + 4  as   x^2 + 2x + 1^2 - 1^2 = -4, or
                                              (x+1)^2 = -3
or                                            x+1 =i*(plus or minus sqrt(3))

or                                            x = -1 plus or minus i*sqrt(3)

This problem, like any other quadratic equation, has two roots.  Note that the fourth possible answer constitutes one part of the two part solution found above.
3 0
3 years ago
A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1200 hours and a standar
a_sh-v [17]

Answer:

The bulbs should be replaced each 1060.5 days.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1200, \sigma = 60

How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?

This is the first percentile, that is, the value of X when Z has a pvalue of 0.01. So X when Z = -2.325.

Z = \frac{X - \mu}{\sigma}

-2.325 = \frac{X - 1200}{60}

X - 1200 = -2.325*60

X = 1060.5

The bulbs should be replaced each 1060.5 days.

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3 years ago
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laila [671]

Answer:

10

Step-by-step explanation:

it is 10 2000÷10=200

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Answer:

Step-by-step explanation:

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