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2 years ago

Write an inequality comparing 3/4 and 2/4.

Mathematics

1 answer:

Furkat [3]2 years ago

7 0

Answer:

3/4 > 2/4

Step-by-step explanation:

3/4 = 0.75

2/4 = 0.5

Therefore, 3/4 > 2/4

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Cross products question, 3/5 over x multiplied by 12 over 20<br> what is x

Nitella [24]

Answer:

9/25x

Step-by-step explanation:

3/5/x ×12/20

3/5×1/x ×12/20

36/100x

Divide both by 4

9/25x

The exact value of x cannot be determined because we don't know what the equation is equated to

So we will have to leave the answer as 9/25x

7 0

2 years ago

Round the following to the nearest cent: $16.997

Paul [167]

$\$16.99\underbrace{7}_{>5}\approx\$17.00$

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2 years ago

SQRT is a parallelogram. If m∠QST = 72°, which of the following statements is true?

Mrrafil [7]

The answer to your question is option b because opposite angles in a quadrilateral are equal to one another

7 0

2 years ago

Read 2 more answers

Find the volume of the solid.

dmitriy555 [2]

In Cartesian coordinates, the region (call it $R$ ) is the set

$R = \left\{(x,y,z) ~:~ x\ge0 \text{ and } y\ge0 \text{ and } 2 \le z \le 4-x^2-y^2\right\}$

In the plane $z=2$ , we have

$2 = 4 - x^2 - y^2 \implies x^2 + y^2 = 2 = \left(\sqrt2\right)^2$

which is a circle with radius $\sqrt2$ . Then we can better describe the solid by

$R = \left\{(x,y,z) ~:~ 0 \le x \le \sqrt2 \text{ and } 0 \le y \le \sqrt{2 - x^2} \text{ and } 2 \le z \le 4 - x^2 - y^2 \right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\sqrt2} \int_0^{\sqrt{2-x^2}} \int_2^{4-x^2-y^2} dz \, dy \, dx$

While doable, it's easier to compute the volume in cylindrical coordinates.

$\begin{cases} x = r \cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \end{cases} \implies \begin{cases}x^2 + y^2 = r^2 \\ dV = r\,dr\,d\theta\,d\zeta\end{cases}$

Then we can describe $R$ in cylindrical coordinates by

$R = \left\{(r,\theta,\zeta) ~:~ 0 \le r \le \sqrt2 \text{ and } 0 \le \theta \le\dfrac\pi2 \text{ and } 2 \le \zeta \le 4 - r^2\right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\pi/2} \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta \, dr \, d\theta \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta\,dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} r((4 - r^2) - 2) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} (2r-r^3) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \left(\left(\sqrt2\right)^2 - \frac{\left(\sqrt2\right)^4}4\right) = \boxed{\frac\pi2}$

3 0

1 year ago

Given that 3 * 6 = 12 and 2 * 5 = 9, then a * b may be defined as

Anton [14]

Answer:

3 *6=12

3+6=9

9+3=12

2*5=2+5=7

7+2=9

a*b=a+b+a

5 0

2 years ago