Using the elimination method, the value of x in the system of equations is calculated as: 8.
<h3>How to Solve a System of Equations by Elimination?</h3>
To solve a system of equations given using the elimination method, do the following:
Multiply 2x - 5y = 1 by 2 and multiply -3x + 2y = -18 by 5 to get the following:
4x - 10y = 2 --> eqn. 1
-15x + 10y = -90 --> eqn. 2
Add
-11x = -88
Divide both sides by -11
x = 8
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Answer:
72
Step-by-step explanation:
you take 48 divided by 4 which is 12 then you take 12 times 6 to get 72
Y= -3/4x + b
2 = -3/4(8) + b
2 = -6 + b
add 6 to both sides and you get
8 = b
so Y=-3/4+8
f(x) = 2(x^2 + 14x + ) - 5 2 is taken out of first 2 terms.
f(x) = 2(x^2 + 14x + (14/2)^2 ) - 5 - 2(14/2)^2
<em><u>2 steps </u></em>
- Inside the brackets: Linear term's coefficient (14) divided by 2 and squared
- Outside the brackets: (14/2)^2 multiplied by 2 and subtract so that there is no change in the value of the quadratic.
f(x) = 2*(x + 7)^2 - 103
The graph is of the original quadratic.