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3 years ago

(-3x)²-(3x-2)²-6*(2x-1.5)

1 answer:

4 0

Without the instructions, I can only assume that you are to "expand the given expression."

Following order of operations rules requires that (3x-2)^2 and -6(2x-1.5) be evaluated first.

(3x-2)^2 = 9x^2 - 12x + 4 and -6(2x-1.5) = -12x + 9

Then we have 9x^2 - (9x^2 - 12x + 4) -12x + 9

the 9x^2 terms cancel, leaving us with 12x - 4 - 12x + 9 = 5 (answer)

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liraira [26]

The expression $-2\vec C+6\vec D$ in the ordered pair notation is (16,-16).

The vector components of a vector are represented as the ordered pair of its x and y components.

For example, if a vector has x - component 'a' and y- component 'b' , then the ordered pair notation for the vector is (a, b), where the vector is $a \vec i+b \vec j$ .

Now the vector C has its x- component = -2

y- component of C = -1

Therefore, ordered pair notation of C = (-2, -1)

x- component of D = 2

y-component of D = -3

Therefore, ordered pair notation of D = (2,-3)

So the expression $-2\vec C+6\vec D$ = -2 (-2,-1) +6 (2,-3) = (4,2) + (12, -18)

= (16, -16) in the ordered pair notation.

That is, the vector $\bold {-2\vec C+6\vec D}$ is a vector with x-component 16 and y-component -16.

Learn more about vectors at brainly.com/question/3184914

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