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avanturin [10]
3 years ago
9

Does anybody know if that apple watch is actually worth what it costs?

Computers and Technology
2 answers:
monitta3 years ago
6 0
I is definetly not it is over priced and there ar emany differnent versions of the same thing for cheaper
liraira [26]3 years ago
5 0
Most likely not, nothing really is.
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Monster Collector
Lera25 [3.4K]

Answer:

In java:

import java.util.*;

public class Main{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 int monsternum, usernum;

 int count = 0;

 Random rand = new Random();

 String [] monsters = {"wild pikamoo","wild bulbaroar"};

 for(int i =0;i<2;i++){

     monsternum = rand.nextInt(5);  

     System.out.print("A "+monsters[i]+" appears! Guess a number between 1 and 5: ");

     usernum = input.nextInt();

     if(monsternum == usernum){      count++;      System.out.println("Congratulations, you caught a "+monsters[i]+"!");  }

 else{      System.out.println("You almost had it, but the monster escaped.");  }

 

 }

 System.out.println("There are no more monsters to encounter!");

 System.out.println("You caught "+count+" monsters of 2");

 if(count!=2){      System.out.print("Keep training to be the very best!");  }

 else{      System.out.print("You're the monster collector master!");  }

}

}

Explanation:

This declares monster and user number as integers

 int monsternum, usernum;

Initialize count to 0

 int count = 0;

Call the random object

 Random rand = new Random();

Create a string array to save the monster names

 String [] monsters = {"wild pikamoo","wild bulbaroar"};

Iterate for the 2 monsters

 for(int i =0;i<2;i++){

Generate a monster number

     monsternum = rand.nextInt(5);  

Prompt the user to take a guess

     System.out.print("A "+monsters[i]+" appears! Guess a number between 1 and 5: ");

Get user guess

     usernum = input.nextInt();

If monster number and user guess are equal, congratulate the user and increase count by 1

<em>      if(monsternum == usernum){      count++;      System.out.println("Congratulations, you caught a "+monsters[i]+"!");  } </em>

If otherwise, prompt the user to keep trying

<em>  else{      System.out.println("You almost had it, but the monster escaped.");  }  </em>

<em>  } </em>

Print no monsters again

 System.out.println("There are no more monsters to encounter!");

Print number of monsters caught

 System.out.println("You caught "+count+" monsters of 2");

Print user score

<em>  if(count!=2){      System.out.print("Keep training to be the very best!");  } </em>

<em>  else{      System.out.print("You're the monster collector master!");  } </em>

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Answer:

Following is given the code with all necessary descriptions as comments in it. The output is also attached under the code. I hope it will help you!

Explanation:

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