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GenaCL600 [577]
3 years ago
13

10 exponent negative 9 divided by 10 exponent negative 3

Mathematics
1 answer:
anygoal [31]3 years ago
8 0
\frac{x^a}{x^b}=x^{a-b}  \\ x^{-a}= \frac{1}{x^a}  \\  \\  \\  \frac{10^{-9}}{10^{-3}} =10^{-9-(-3)}=10^{-9+3}=10^{-6}= \frac{1}{10^6} = \frac{1}{1000000} =0,000001
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Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (4, −5, 2) and parallel
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Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e (x_o, y_o, z_o) and are parallel to \dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}

The parallel vector to the line i + zj+k = ai + bj + ck

Hence, the equation for the line is :

x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct

x = 4 + t

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Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

\begin  {vmatrix} x = 4+ t   \\ \\  \dfrac{x-4}{1} = t  \begin {vmatirx} \end {vmatrix}\begin {vmatrix} y = - 5+2t  \\ \\ \dfrac{y+5}{2}  =t      \end {vmatrix}\begin {vmatrix} z =2+t  \\ \\ \dfrac{z-2}{1}  =t      \end {vmatrix}

∴

\dfrac{x-4}{1}= \dfrac{y+5}{2}=\dfrac{z-2}{1}

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