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Phoenix [80]
3 years ago
11

What is this math problem??? g(x)=1/20x(x-100)

Mathematics
1 answer:
Fudgin [204]3 years ago
6 0

Answer:

the x intercept is (0,100) and the y intercept is (0,0)

Step-by-step explanation:

g(x)=1/20x(x-100)

g(0)=1/20(0)(0-100)

g(0)=1/20*0(0-100)

g(0)=100

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Answer:

Approximately normal

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

As the sample size is above 30, even though the underlying distribution is right-skewed, the shape of the sampling distribution of the sample means will be approximately normal.

5 0
3 years ago
What is the answer to the equation 4x + - 9 = 74
zzz [600]

Answer:

x = 20.75

Step-by-step explanation:

<u>Step 1:  Solve for x</u>

4x + (-9) = 74

4x - 9 + 9 = 74 + 9

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4 years ago
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3 years ago
PLZZ HELPP ASAP MATH QUESTION SIMPLIFY COMPLEX FRACTION
Ksivusya [100]

Answer:

\large\boxed{\dfrac{x^3+6x}{80x+64}}

Step-by-step explanation:

\dfrac{\frac{1}{8}+\frac{x+4}{16}}{\frac{x+4}{x^2}+\frac{4}{x}}=\left(\dfrac{1\cdot2}{8\cdot2}+\dfrac{x+4}{16}\right):\left(\dfrac{x+4}{x^2}+\dfrac{4\cdot x}{x\cdot x}\right)\\\\=\left(\dfrac{2}{16}+\dfrac{x+4}{16}\right):\left(\dfrac{x+4}{x^2}+\dfrac{4x}{x^2}\right)=\dfrac{2+x+4}{16}:\dfrac{x+4+4x}{x^2}\\\\=\dfrac{x+6}{16}:\dfrac{5x+4}{x^2}=\dfrac{x+6}{16}\cdot\dfrac{x^2}{5x+4}=\dfrac{(x+6)(x^2)}{(16)(5x+4)}\\\\\text{use distributive property}\ a(b+c)=ab+ac

=\dfrac{(x)(x^2)+(6)(x)}{(16)(5x)+(16)(4)}=\dfrac{x^3+6x}{80x+64}

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