Answer: a) An = An-1 + An-2
b) 55ways
Step-by-step explanation:
a) a nickel is 5 cents and a dime is 10cent so a multiple of 5 cents is the possible way to pay the tolls in both choices.
Let An represents the number of possible ways the driver can pay a toll of 5n cents, so that
An = 5n cents
Case 1: Using a nickel for payment which is 5 cents, the number of ways given as;
An-1 = 5( n-1)
Case 2: using a dime which is two 5 cents, the number of ways is given as;
An-2 = 5(n-2)
Summing up the number of ways, we have
An = An-1 + An-2
From the relation,
If n= 0, Ao= 1
n =1, A1= 1
b) 45 cents paid in multiples of 5cents will give us 9 ways(A9)
From the relation, we have that
Ao = 1
A1 = 1
An =An-1 + An-2
Ao = 1
A1 = 1
A2 = A1+Ao = 1+1= 2
A3 = A2 + A1 = 3
A4 = A3+A2=5
A5=A4+A3=8
A6=A5+A4=13
A7 =A6+A5 = 21
A8= A7+A6= 34
A9= A8+A7= 55
So there are 55ways to pay 45cents.
Answer:
(8 times 50)+ (8 times 2)
Step-by-step explanation:
Answer:
ok
Step-by-step explanation:
Given : A inequality is given to us . The inequality is 19 ≥ t + 18 ≥ 11 .
To Find : The correct option between the given ones . To write the compound inequality with integers .
Solution : The given inequality to us is 19 ≥ t + 18 ≥ 11 . Let's simplify them seperately .
⇒ 19 ≥ t + 18 .
⇒ t + 18 ≤ 19 .
⇒ t ≤ 19 - 18 .
⇒ t ≤ 1 = 1 ≥ t . ..................(i)
⇒ t + 18 ≥ 11 .
⇒ t ≥ 11 - 18.
⇒ t ≥ -7 . ....................(ii)
<u>On</u><u> </u><u>combing</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>&</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>.</u>
This means that t is less than or equal to 1 but greater than or equal to (-7) .
Answer:
5^6
Step-by-step explanation:
5 was multiplied repeatedly 6 times, so it's 5 to the power of 6
