Answer:
la app es la mejor gracias
Step-by-step explanation:
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8n = -3m + 1
n = -2, 2,4
first add -2, 2 and 4 which = 4
then do 8(4) = -3m +1 which makes 24 = -3m +1 so subtract 1 on both sides then you have 23 = -3m divde -3 on both sides which equal -7.66 or 8
1. The problem indicates that 300 pounds of oranges were purchased at $0.24 per pound, so the cost is:
300x$0.24=$72
2. A percent of 21% spoilage is expected, which means that 89% of 300 pounds of oranges left, is:
300x0.89=267 pounds of oranges
3. We want to calculate the selling price per pound of 267 pounds of oranges, so let's call this value "x":
Markup %=(Markup/cost)x100
Markup=267x-72
4. The desired markup, based on selling price, is 50%. So, when we substitute the values, we obtain:
(267x-72/72)x100=50
5. Let's clear the "x":
(26700x-7200/72)=50
26700x-7200=50x72
26700x-7200=3600
26700x=3600+7200
x=10800/26700
x=$0.40
x=40 cents
What should the selling price per pound be?
The answer is: 40 cents or $0.40
Answer:
z = 30
Step-by-step explanation:
WX and VU are congruent
2z + 10 = z + 45
subtract z from both sides (z + 10 = 45)
subtract 10 from both sides (z = 30)
the answer is z = 30
Answer:
Step-by-step explanation:
Let x be the random variable representing the number of miles that each person walked each day for 6 months. Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,
z = (x - µ)/σ
Where
x = sample mean
µ = population mean
σ = standard deviation
For Rueben,
µ = 5
σ = 1.1
the probability that Rueben walked more than 6.1 miles is expressed as
P(x > 6.1) = 1 - P( x ≤ 6.1)
For x = 6.1,
z = (4 - 6.1)/1.1 = - 1.91
Looking at the normal distribution table, the probability corresponding to the z score is 0.02807
P(x > 6.1) = 1 - 0.02807 = 0.97193
P(x > 6.1) = 0.97 × 100 = 97%
For Victor,
µ = 4.4
σ = 1.4
the probability that Victor walked less than 5.8 miless is expressed as
P(x < 5.8)
For x = 5.8,
z = (5.8 - 4.4)/1.4 = 1
Looking at the normal distribution table, the probability corresponding to the z score is 0.8413
P(x < 5.8) = 0.84 = 84%