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3 years ago

Where is +1 on a positive and negative number line

Mathematics

2 answers:

lyudmila [28]3 years ago

4 0

The right, because your going forward not backwards

Whitepunk [10]3 years ago

3 0

Answer:

+1 will be on the right side.

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Find S5 for a geometric series for which a1=81 and r=1/9.

Minchanka [31]

ANSWER

$S_5=91\frac{10}{81}$

EXPLANATION

The sum of the first $n$ terms of a geometric sequence is given by;

$S_n=\frac{a_1(1-r^n)}{1-r} ,-1$

Where $n$ , is the number of terms and $a_1$ is the first term.

When $n=5$ , we have $a_1=81$ , we get;

$S_5=\frac{81(1-(\frac{1}{9})^5)}{1-\frac{1}{9}}$

$S_5=\frac{81(1-\frac{1}{59049})}{1-\frac{1}{9}}$

$S_5=\frac{81(\frac{59048}{59049})}{\frac{8}{9}}$

$S_5=\frac{7381}{81}$

$S_5=91\frac{10}{81}$

6 0

2 years ago

Fraction of ratio 4 : 5

vladimir1956 [14]

It is 80% because 4/5

3 0

2 years ago

Help please i don’t know how to do it

Norma-Jean [14]

Answer:

Step-by-step explanation:

$\frac{dy}{dx}=x^{2}(y-1)\\\frac{1}{y-1} \text{ } dy=x^{2} \text{ } dx\\\int \frac{1}{y-1} \text{ } dy=\int x^{2} \text{ } dx\\\ln|y-1|=\frac{x^{3}}{3}+C\\$

From the initial condition,

$\ln|3-1|=\frac{0^{3}}{3}+C\\\ln 2=C$

So we have that $\ln |y-1|=\frac{x^{3}}{3}+\ln 2\\e^{\frac{x^{3}}{3}+\ln 2}=y-1\\2e^{\frac{x^{3}}{3}}=y-1\\y=2e^{\frac{x^{3}}{3}}+1$

4 0

2 years ago

A cab company charges a flat amount of $5 plus $1.10 per mile traveled. If at the end of a cab ride a customer owes the driver $

Luda [366]

I believe that the number of miles traveled would be 8. This is because you would subtract $5.00 from the $13.80 and then divided by $1.10.

8 0

2 years ago

Help me please!!! I'll give brainlist and thanks! Just please help me!!

Alex_Xolod [135]

Answer:How many fives are in 15? ... How many three-fourths are in 2? ... There are 6 half-sized pieces in 3 wholes. ... and we can see that there are 4 wholes with 6 sixths in each whole, so there are 4\times 6 = 24 sixths in 4. ... Each whole yields a two-thirds and one half of another two-thirds, therefore 3 sets of two-thirds can be ...

Step-by-step explanation:

8 0

2 years ago