The answer is C
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Answer:
<h2>infinitely many solutions</h2>
Step-by-step explanation:
5x - 6 = 3x - 6 + 2x <em>combine like terms</em>
5x - 6 = (3x + 2x) - 6
5x - 6 = 5x - 6 <em>subtract 5x from both sides</em>
-6 = -6 TRUE
Therefore the equation has infinitely many solutions.
<span>The next letter is 'n'. The pattern misses a letter after a pair of letters, for example: 'a' and 'b' are a letter pair, then 'c' is skipped, then the letter pair 'd' and 'e' comes next. For every other letter pair, the order is reversed so they are not in alphabetical order. The next letter pair is 'm' and 'n', and because the pair 'j' and 'k' is in alphabetical order, this pair must be reversed. Therefore, the next letter is 'n'.</span>
Answer:
3b-10=20
Step-by-step explanation:
3b-10=20
3b-10+10=20+10
3b=30
3b/3=30/3
b=10
Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
