All categories

3 years ago

Please help asap!!!!

Mathematics

1 answer:

pentagon [3]3 years ago

3 0

Answer:

A.) 2

B.) 0

C.) 1/3

D.) 1.25

Step-by-step explanation:

A.) 5(2/3)= 2

B.) 5-5= 0

C.) 2(2/3)-1= 1/3

D.) (1/2)+3/4= 1.25

Hope This Helps! Have A Nice Day!!

You might be interested in

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Ne4ueva [31]

Slope of AD = (2k - 0)/(2j -b - 0) = 2k/(2j - b)
slope of BC = (2k - 0)/(2j - b) = 2k / (2j - b)
AD ║ BC (same slope)

Slope of AB = 0
Slope of DC = 0

AB║DC

7 0

3 years ago

Read 2 more answers

What is the repeating or terminating decimal that is equivalent to 11/36

Oduvanchick [21]

Answer:

0.30555555....

Step-by-step explanation:

(The fives keep on coming, this is a repeating decimal.)

3 0

3 years ago

It is customary to give a 15% tip for a meal at a restaurant. what is 15% of $64.40

alex41 [277]

Answer:

$9.66 isb15% of $64.40

Step-by-step explanation:

64.40×15%

7 0

1 year ago

Please help with this arc equation.

boyakko [2]

Answer:

Part 1) $arc\ AB=49^o$

Part 2) $arc\ ABC=204^o$

Part 3) $arc\ BAC=156^o$

Part 4) $arc\ ACB=311^o$

Step-by-step explanation:

Part 1) Find the measure of arc AB

we know that

$arc\ AB=m\angle AOB$ ----> by central angle

we have

$m\angle AOB=49^o$

therefore

$arc\ AB=49^o$

Part 2) Find the measure of arc ABC

we know that

The central angle of complete circle is equal to 360 degrees

$arc\ ABC=360^o-107^o-49^o=204^o$

Part 3) Find the measure of arc BAC

we know that

$arc\ BAC=arc\ BA+arc\ AC$ ----> by angle addition postulate

we have

$arc\ BA=49^o$ ---> by central angle

$arc\ AC=107^o$ ---> by central angle

$arc\ BAC=49^o+107^o=156^o$

Part 4) Find the measure of arc ACB

we know that

The central angle of complete circle is equal to 360 degrees

$arc\ ACB=360^o-arc\ AB$

substitute

$arc\ ACB=360^o-49^o=311^o$

4 0

3 years ago

Let the function f be continuous and differentiable for all x. Suppose you are given that f(−1)=−3, and that f'(x) for all value

Monica [59]

Answer:

Step-by-step explanation:

By MVT,

$f'(c) = \frac{f(5)-f(-1)}{5-1}$

$4f'(c)= f(5) + 3\rightarrow f(5) = 4f'(c) - 3$

Moreover, $f'(x)\leq 4~~~~~~ \forall x,$

$f(5) \leq 16 - 3 =13$

Hence the largest possible value of f(5) is 13

8 0

3 years ago