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4 years ago

Please help me!!!!!!!

Mathematics

1 answer:

Helen [10]4 years ago

6 0

First we will find the value of x.

To find the value of x we can add angle Q and angle O and set them equal to 180 and solve for x.

We will be setting them equal to 180 since the opposite angles of an inscribed quadrilateral are supplementary.

angle Q + angle O = 180
6x - 5 + x + 17 = 180
7x +12 = 180
7x = 168
x = 24

Now we can use 24 for x and find the value of angle QRO

angle QRO = 2x + 19
angle QRO = 2(24) + 19
angle QRO = 48 + 19
angle QRO = 67

So the answer choice B is the right answer.

Hope this helps :)<span />

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Step-by-step explanation:

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In ΔABC shown below, ∠BAC is congruent to ∠BCA: Triangle ABC, where angles A and C are congruent Given: Base ∠BAC and ∠ACB are c

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3 years ago

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Identify the equation of the circle that has its center at (7, -24) and passes through the origin.

krok68 [10]

The equation of this line would be (x - 7)^2 + (y + 24)^2 = 625

This is because of the base equation for circles, which is:

(x - x1)^2 + (y - y1)^2 = r^2

In which, x1 is the x-coordinate to the center, y1 is the y-coordinate to the center and r is the radius.

So we start by putting in out known values.

(x - 7)^2 + (y + 24)^2 = r^2

However, we still don't know the r value. To find it, we must use the Pythagorean Theorem to find the distance between the center and the origin.

a^2 + b^2 = c^2

7^2 + 24^2 = c^2

49 + 576 = c^2

625 = c^2

25 = c

So we know the radius must be 25. So we can plug that into what we already had.

(x - 7)^2 + (y + 24)^2 = 25^2

(x - 7)^2 + (y + 24)^2 = 625

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