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3 years ago

Which expression is equal to 24-(-6) NEED ANSWER ASAP!!

Mathematics

1 answer:

LenaWriter [7]3 years ago

8 0

Answer:

30, 24+6

Step-by-step explanation:

So the negative in front of the parentheses turns it into a positive number.

Sorry, cannot be explained more!

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Simplify 10(x + 4) + 15(x + 1)

motikmotik

Answer:

25x + 55

Step-by-step explanation:

10(x + 4) + 15(x + 1)

Distribute

10x + 40 + 15x +15

Combine like terms

25x + 55

8 0

2 years ago

Read 2 more answers

A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain

AysviL [449]

Answer:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

Step-by-step explanation:

For this case we have the following value:

$R = 0.0498 \frac{Kpa}{Km}$

We can convert this first to $\frac{Kpa}{m}$ like this:

$R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}$

Now we use the fact the the pressure is defined as $P =\frac{F}{A}$ , whre P is the pressure, F the force and A the area, so then $Kpa= \frac{KN}{m^2}$ and then we can replace this:

$R=0.0000498 \frac{KN}{m^3}$

Now from definition of work we know that $W= Fd$ where W is the work, F the force and d the distance, so then is equivalent $KN =\frac{KJ}{m}$

And if we replace this into the equation we got:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

4 0

3 years ago

Provide the measure of each angle in quadrilateral RSTU

Vikentia [17]

Answer:

R = 112, S = 64, T = 58, U = 126

Step-by-step explanation:

Quadrilateral ABCD is reflected to create quadrilateral RSTU

The angles are all the same

Since a quadrilateral equals up to 360

112+64+58=234

360-234=126

6 0

3 years ago

I - 6. Select from the options below to correctly complete the statement. Figure 1 can be transformed into Figure 2 by a followe

Agata [3.3K]

Answer:

you still need help ?

Step-by-step explanation:

4 0

2 years ago

Find cot theta. (-6,-3sqrt(5)

cupoosta [38]

0 Pretend that is theta XD

cot 0 = $\frac{1}{tan0}$

Find tan 0.

tan 0 = $\frac{y}{x}$

tan 0 = $\frac{-3\sqrt{5}}{-6}$

tan 0 = $\frac{\sqrt{5}}{2}$

cot 0 = $\frac{1}{tan0}$

cot 0 = $\frac{1}{\frac{\sqrt{5} }{2} }$

Multiply 2/√5 to the numerator and the denominator (or multiply the reciprocal of the denominator to the top and bottom of the fraction)

cot 0 = $\frac{1}{\frac{\sqrt{5}}{2} } (\frac{\frac{2}{\sqrt{5}} }{\frac{2}{\sqrt{5}}} )$

cot 0 = $\frac{2}{\sqrt{5}}$

Multiply √5 to the numerator and the denominator

cot 0 = $\frac{2}{\sqrt{5}} (\frac{\sqrt{5} }{\sqrt{5} })$

cot 0 = $\frac{2\sqrt{5}}{5}$

5 0

2 years ago