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worty [1.4K]
3 years ago
7

Find the coordinates of point, P, which divides the line segment from A = (0, 4) to B = (6, 8) in a ratio of 2:1.

Mathematics
1 answer:
anastassius [24]3 years ago
6 0
When a point divide a line segment A (x1,y1) B (x2,y2) into a ration of a:b, the coordinates of that point is x1+[a/(a+b)](x2-x1), y1+[a/(a+b)](y2-y1)
so x=0+(2/3)(6-0)=4
y=4+(2/3)(8-4)=6&2/3 (mixed number 6 and 2 over 3)
(4, 6&2/3) is the answer. 
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Gregory sees an $80.00 jacket on sale at 30% off. How much will it cost after a 7% sales tax? $56.00 $59.92
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The graph of g(x) is a reflection and translation of ∛x see attachment, please help
svetoff [14.1K]
<h2>Hello!</h2>

The answer is: g(x)=-\sqrt[3]{x-1}

<h2>Why?</h2>

Let's check the roots and the shown point in the graphic (2,-1)

First,

0=-\sqrt[3]{x-1}\\\\0^{3}=(-\sqrt[3]{x-1})^{3}\\\\0=-(x-1)\\\\x=1

then,

g(0)=-\sqrt[3]{0-1}\\g(0)=-(-1)\\g(0)=1\\y=1

So,  we know that the function intercepts the axis at (1,0) and (0,1), meaning that the function match with the last given option

(g(x)=-\sqrt[3]{x-1})

Second,

Evaluating the function at (2,-1)

y=-\sqrt[3]{x-1}\\-1=-\sqrt[3]{2-1}\\-1=-\sqrt[3]{1}\\-1=-(1)\\-1=-1

-1=-1

It means that the function passes through the given point.

Hence,

The equation which represents g(x) is g(x)=-\sqrt[3]{x-1}

Have a nice day!

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