Just solve the square roots and compare all four to see which one is the normalest
Answer:
x = 12
Step-by-step explanation:
130 + y = 180 {linear pair}
y = 180 - 130
y = 50°
3x - 6 +8x + 4 + 50 = 180 {Angle sum property of triangle}
3x + 8x - 6 + 4 + 50 = 180 {Combine like terms}
11x + 48 = 180
11x = 180 - 48
11x = 132
x = 132/11
x = 12°
The surface area would be 166.
Answer:
The answers to the first question are A,C,D
The answer to the second question is YZ=16
Step-by-step explanation:
(1st Question)
Since <K and <M Are equal, and both <L's are equal, KL and ML are congruent (Answer choice) because of the ASA postulate.
You need to create the following equation to find the length of KN and MN 7x-4=5x+12
(Get the "x" variable to one side)
2x-4=12
(Isolate the variable)(Remove the 4)
2x=16
(Divide the 2 by itself to remove it from the x, remember to divide both sides by 2)
x=8 (Answer Choice)
Plug in the x value into each equation
KN= 7(8)-4
KN= 56-4
KN= 52
MN= 5(8)+12
MN= 40+12
MN= 52 (Answer Choice)
MN=KN
(Second Question)
Since XWY(20) is half of XWZ(40), ZWY also equals 20.
This now proves the triangle is congruent by the AAS postulate.
Since the triangles are congruent, if XY = 16, YZ also equals 16.
Answer:the balance after 7 years is $3216
Step-by-step explanation:
A) Initial amount deposited into the account is $2800 This means that the principal,
P = 2800
It was compounded yearly. This means that it was compounded once in a year. So
n = 1
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
It was compounded for 7 years. So
t = 7
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years. Therefore
A = 2800(1 + 0.04/2)^ 1× 7
A = 2800(1 + 0.02)^7
A = 2800(1.02)^7
A = $3216
