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velikii [3]
2 years ago
15

Find the x and y intercepts.

Mathematics
1 answer:
Roman55 [17]2 years ago
3 0
-3/4x + 5/6 y = 15

Multiply through by 6

-9/2x + 5y = 90

Add 9/2x to both sides

5y = 90 + 9/2x

Divide both sides by 5

y = 18 + 9/10x

y = 9/10x + 18
Comparing with the general equation of a straight line y = mx + c

Gradient (m) = 9/10 or 0.9
and the y - intercept (c) = 18




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HELP FAST LAST QUESTION ON TEST!!! The front lawn of NPHS has a roped off area of 2x? - 11x + 15. What are the
nexus9112 [7]

Answer:the area is = the length*the width

2x^2-11x+15= (2x-5)* the width

you have to divide 2x^2 - 11 x + 15 at 2x-5

2x^2-11x+15   |  2x-5

-2x*2+5x                 x-3

-------------

/       -6x+15

       +6x-15

-----------------

         /   /

the answer is X-3

Step-by-step explanation:

6 0
2 years ago
A and B are independent events. P(A) = 0.30. P(B) = 0.60 What is P(A/B)?
Tomtit [17]

Answer:

A and B are independent events.

P(A) = 0.30. P

8 0
3 years ago
Possible
Alecsey [184]
<h3>Answer:  Independent</h3>

For two events A and B, if the occurrence of either event in no way affects the probability of the occurrence of the other event, then the two events are considered to be <u>  independent  </u> events.

=========================================================

Explanation:

Consider the idea of flipping a coin and rolling a dice. If these actions are separate (i.e. they don't bump into each other), then one object won't affect the other. Hence, one probability won't change the other. We consider these events to be independent.

In contrast, let's say we're pulling out cards from a deck. If we don't put the first card back, then the future probabilities of other cards will change. This is considered dependent.

3 0
1 year ago
PLEASE HELP AND PLEASE DON'T GUESS!!!!!
Goshia [24]
The answer is D., a dummod deleted my answer that has alot of thanks and ratings.
4 0
2 years ago
What is the result when the following code is run? double x = 1; double y = 1; int i = 0; do { y = x / 2; x = x + y; i = i + 1;
Mama L [17]

Answer:

The answer is: 3

Step-by-step explanation:

1. At the begining of the program we start by declairing the variables:

 double x=1, double y=1 and int i=0.

2. The structure do...while is used to defined the loop. x<2.5 is the finalization condition of the loop. i is the counter of the loop.

y=x/2 is the first calculation

x=x+y is the second one. Here is where the values of the variable x changes.

a) for the first iteration, the values of y and x are shown below:

\\\\x=1\\y=1\\y=1/2=0.5\\x=1+0.5=1.5\\i=1

The variable x is minor to 2.5 so the loop will continue computing.

b)   the second iteration, the values of y and x are shown below::

 y=0.5\\x=1.5\\y=\frac{1.5}{2}=0.75\\ x=1.5+0.75=2.25\\i=2

The variable x is still minor to 2.5 so the loop will continue computing.

c) third iteration:

y=0.75\\x=2.25\\y=\frac{2.25}{2} =1.1125\\x=2.25+1.125=3.375\\i=3

The condition x<2.5 is not true so the loop ends.

3. System.out.print(i + " "); displays the value of the variable i wich value is 3.

Therefore the number 3 is display.

6 0
2 years ago
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