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velikii [3]
3 years ago
15

Find the x and y intercepts.

Mathematics
1 answer:
Roman55 [17]3 years ago
3 0
-3/4x + 5/6 y = 15

Multiply through by 6

-9/2x + 5y = 90

Add 9/2x to both sides

5y = 90 + 9/2x

Divide both sides by 5

y = 18 + 9/10x

y = 9/10x + 18
Comparing with the general equation of a straight line y = mx + c

Gradient (m) = 9/10 or 0.9
and the y - intercept (c) = 18




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Answer

6

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Elimination method: ax+by=r, -bx+cy=s
Alex17521 [72]
\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]

Isolate x for ax+by=r

x= \frac{r-by}{a} ; a \neq 0

Subsititute x= \frac{r-by}{a}

-b \frac{r-by}{a} +cy=s

Isolate r for : -b \frac{r-by}{a}+cy=s

r=- \frac{as-acy-b^2y}{b} ; a \neq 0;b \neq 0

For x : \frac{r-by}{a}

Subsititute r = - \frac{as-acy-b^2y}{b}

x= -\frac{as-acy-b^2y}{b}/a

x =  \frac{cy-s}{b}

The solutions to the system of equations are:

r= -\frac{as-acy-b^2y}{b} and <span> x = \frac{cy-s}{b}
</span>
hope this helps!


3 0
3 years ago
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