Answer:
a) s = -16
+ 192t + 96
b) Height of the football after 2 seconds is 448 feet.
ii. The football would not hit the ground after 2 seconds.
Step-by-step explanation:
Given:
s = -16
+
t + 
where: s is the height of the football above the ground, t is the time,
is the initial velocity and
is the initial height.
The height of the building =
= 192 feet and the initial speed of the ball =
= 96 feet per second, then;
s = -16
+ 192t + 96
a) The polynomial is given as:
s = -16
+ 192t + 96
b) The height of the football when t = 2 seconds is;
s = -16(2) + 192(2) + 96
= -32 + 384 + 96
= -32 + 480
s = 448
The height of the football when t = 2 seconds is 448 feet.
ii. The football would not hit the ground after 2 seconds.
The answer is 9 for this one
Midpoint formula
(x2-x1 / 2) , (y2-y1/ 2)
x = 4-(-2) / 2 = 3
y= -6-2 / 2= -4
midpoint (3, -4)
That’s cool. i need p01nts so imma comment