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sveta [45]
3 years ago
15

How does scale factor affect the change in area?​

Mathematics
1 answer:
MrRa [10]3 years ago
7 0
<h3>Answer:</h3>

<u>It squares the amount you scaled it by.</u>

<h3>Step-by-step explanation:</h3>

For example, imagine that you had 2 by 2 square, and then you put it through a scale factor of 2.

Now each side length would be double of what it once was.

But when you multiply the new lengths together, the area would be of 4 times more.

(Original Equation)  2 * 2 = 4

(Scale Factor of 2)   4 * 4 = 16

So when the scale factor is made, the area would be squared to the multiple that you scaled it by.

<em>***A square root is a number times itself.</em>

<em>(eg): 3 * 3 = </em><em>9</em>

<em>        15 * 15 = </em><em>225</em>

<em>9 and 225 would be the square root in these problems.</em>

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1/2 the weight of a brick +20= 1/3 the weight of a brick +30. What is the weight of the brick?
prisoha [69]
1/2x+20=1/3x+30
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6 0
3 years ago
1. f(x) = 3x – 2; f(4)??
netineya [11]

Answer:

the answer is 5

Step-by-step explanation:

f(4) = 3(4) -2

7 - 2 = 5

8 0
3 years ago
Read 2 more answers
Deijah gave Isaiah $6.25 in nickels and quarters. If 12 coins were quarters, how many coins were nickels? Which equation models
dem82 [27]
Deijah has $6.25. 

Now, this 6.25 is comprised of 0.05s and 0.25s. 
We know that there are 12 0.25s.

We now want to know how many remaining 0.05s there are.

Again, we know that the number of 0.05s he has, which is 12, multiplied by 0.05, plus the number of 0.25s he has, multiplied by 0.25, equals 6.25.

Thus, the answer is A, 0.25 x 12 + 0.05 x n = 6.25.
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3 years ago
Let v be an eigenvector of a matrix A with a corresponding eigenvalue ?=2. Find one solution x of the system Ax=v.
Murljashka [212]

Answer with explanation:

For, a Matrix A , having eigenvector 'v' has eigenvalue =2

 The order of matrix is not given.

It has one eigenvalue it means it is of order , 1×1.

→A=[a]

Determinant [a-k I]=0, where k is eigenvalue of the given matrix.

It is given that,

k=2

For, k=2, the matrix [a-2 I] will become singular,that is

→ Determinant |a-2 I|=0

→I=[1]

→a=2

Let , v be the corresponding eigenvector of the given eigenvalue.

→[a-I] v=0

→[2-1] v=[0]

→[v]=[0]

→v=0

Now, corresponding eigenvector(v), when eigenvalue is 2 =0

 We have to find solution of the system

→Ax=v

→[2] x=0

→[2 x] =[0]

→x=0, is one solution of the system.

5 0
3 years ago
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